地址:http://acm.split.hdu.edu.cn/showproblem.php?pid=6071 题目: Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 144    Accepted Submission(s): 62 Problem Description In HDU, you have…

给你一个4个点的环,问你从2号点出发, 再回到2号点,长度>=K的最短路是多少.环上的边长度不超过30000. 跑出来所有dis(2,j)以后,然后for一遍j,根据dis(2,j)+t*2*w>=K,解出来对于每个j而言最小的t,然后尝试更新答案即可.如果dis(2,j)已经大于等于K了,那直接用其尝试更新答案. 跟CDOJ1633很像. #include<cstdio> #include<queue> #include<algorithm> #inclu…

In HDU, you have to run along the campus for 24 times, or you will fail in PE. According to the rule, you must keep your speed, and your running distance should not be less than K meters. There are 4 checkpoints in the campus, indexed as p1,p2,p3 and…

Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 101    Accepted Submission(s): 40 Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in PE…

lazy running(最短路) 题意: 一个环上有四个点,从点2出发回到起点,走过的距离不小于K的最短距离是多少 \(K <= 10^{18} 1 <= d <= 30000\) 看完这道题,觉得这是个智力题,想了一想,无从下手啊 每次总是看完题解,就豁然开朗 其实之前做过一个类似的题,题目 但是根本想不到第一步, 选2w来转换啊,而且也不知道正确性啊 这类题要仔细理解一番 #include<bits/stdc++.h> #define LL long long #def…

Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 1384    Accepted Submission(s): 597 Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in…

Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others) Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in PE. According to the rule, you must keep your speed, and…

/* HDU 6071 - Lazy Running [ 建模,最短路 ] | 2017 Multi-University Training Contest 4 题意: 四个点的环,给定相邻两点距离,问从2号点出发,2号点结束,距离大于k的最短距离 d(i,j) < 30000, k <= 1e18 分析: 设 r = min(d(1,2), d(2,3)) 假设距离 k 可达,则 k+2*r 也可达(来回走的形式) 故求出所有 d[i][j] 满足 d[i][j]%2r == j 的最短距离…

关于几个的区别和联系:http://www.cnblogs.com/zswbky/p/5432353.html d.每组的第一行是三个整数T,S和D,表示有T条路,和草儿家相邻的城市的有S个(草儿家到这个城市的距离设为0),草儿想去的地方有D个: 求D个城市中距离草儿家最近的距离. s.进行1次单源最短路,找出距离最小的即可. c.Dijkstra单源最短路 /* Dijkstra单源最短路 权值必须是非负 单源最短路径,Dijkstra算法,邻接矩阵形式,复杂度为O(n^2) 求出源beg到所…

Lazy Running Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 524288/524288 K (Java/Others)Total Submission(s): 657    Accepted Submission(s): 284 Problem Description In HDU, you have to run along the campus for 24 times, or you will fail in P…