问一个无向图中去掉任意两点后剩下的连通分量的个数最大值 枚举第一个删去的点,在剩下的子图中求割点 注意,剩下的子图可能不连通,那么就要对每个连通块求割点 计算删去一个点后剩余连通分量个数 left 的方法为:tarjan算法中的时间戳数组dfn[]若为0说明是新的连通分量 求删去割点后剩余连通分量个数: tarjan算法中将判断是否为割点的bool 数组改为int类型,并将iscut[i] = 1 改为 iscut[i]++ 即可 那么对于非根节点,删去后剩余个数为iscut[i] + 1(子树…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4587 题目给了12000ms,对于tarjan这种O(|V|+|E|)复杂度的算法来说,暴力是能狗住的.可以对每个点进行枚举,然后对剩余的网络进行tarjan,对割点所能造成的最大的连通分量进行查询,也就是如下的方程.ans=max{cut[i]}+cnt 其中cnt删除第一个结点之后剩下的网络在初始时刻的连通分量的数量,也就是对每一个第一结点tarjan进行深搜的次数.另外,这次的tarjan中的…

POJ1144 网络 description: 给出一张\(N\)个点的无向图,求其中割点的个数 data range: \(N\le 100\) solution: 一道模板题(但是读入实在是把我恶心坏了) #include<cstdio> #include<vector> #include<algorithm> #include<iostream> #include<sstream> using namespace std; const in…

Given a complete binary tree, count the number of nodes. Definition of a complete binary tree from Wikipedia: In a complete binary tree every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as po…

Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only nod…

Given a linked list, swap every two adjacent nodes and return its head. For example,Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, onl…

Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list, on…

#24. Swap Nodes in Pairs Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify t…

问题: Given a linked list, reverse the nodes of a linked list k at a time and return its modified list. If the number of nodes is not a multiple of k then left-out nodes in the end should remain as it is. You may not alter the values in the nodes, only…

问题: Given a linked list, swap every two adjacent nodes and return its head. For example, Given 1->2->3->4, you should return the list as 2->1->4->3. Your algorithm should use only constant space. You may not modify the values in the list…