URAL 2069 Hard Rock (最短路)】的更多相关文章

题意:给定 n + m 个街道,问你从左上角走到右下角的所有路的权值最小的中的最大的. 析:我们只要考虑几种情况就好了,先走行再走列和先走列再走行差不多.要么是先横着,再竖着,要么是先横再竖再横,要么是先横再竖再横再竖,全考虑一下就好了. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cs…
2069. Hard Rock Time limit: 1.0 secondMemory limit: 64 MB Ilya is a frontman of the most famous rock band on Earth. Band decided to make the most awesome music video ever for their new single. In that music video Ilya will go through Manhattan standi…
题解及证明:http://www.cnblogs.com/StupidBoy/p/5241258.html #include<cstdio> #include<algorithm> using namespace std; int n,m,a[100100],b[100100]; int main() { //freopen("h.in","r",stdin); scanf("%d%d",&n,&m); f…
Meeting Time limit: 2.0 secondMemory limit: 64 MB K friends has decided to meet in order to celebrate their victory at the programming contest. Unfortunately, because of the tickets rise in price there is a problem: all of them live in different part…
Black Spot Time limit: 1.0 secondMemory limit: 64 MB Bootstrap: Jones's terrible leviathan will find you and drag the Pearl back to the depths and you along with it. Jack: Any idea when Jones might release said terrible beastie? Bootstrap: I already…
题目链接 \(Description\) 给定一张带权图(边是双向的,但不同方向长度不同).求从1出发,至少经过除1外的一个点,再回到1的最短路.点和边不能重复经过. \(n\leq5000,m\leq10000\). \(Solution\) 最短路自然是从1走到一个点,然后从这个点通过最短路到达另一个点,再回到1. 我们把与1相邻的点都标记为关键点,然后把1从图中删去,就成了求任意一对关键点之间的最短路. 显然不能枚举每个点跑最短路.但注意给每个点设一个初始距离,我们是可以跑多源最短路的.…
1741. Communication Fiend Time limit: 1.0 second Memory limit: 64 MB Kolya has returned from a summer camp and now he's a real communication fiend. He spends all his free time on the Web chatting with his friends via ICQ. However, lately the protocol…
题目:https://www.lydsy.com/JudgeOnline/problem.php?id=2069 首先,对于和 1 相连的点,一定是从某个点出发,回到另一个点: 所以需要枚举起点和终点,但做 n 遍 dijkstra 不太可行: 可以进行多起点最短路,一次知道了以一些点作为起点.另一些点作为终点的答案: 于是问题是如何划分起点和终点,使一定能找到最优解: 二进制划分,枚举每一位,这一位是 0/1 分成两部分,那么任意不同的两个数一定某一次被分到了不同的集合: 具体做法可以是从 1…
题目传送门 /* 题意:程序从1到n版本升级,正版+正版->正版,正版+盗版->盗版,盗版+盗版->盗版 正版+破解版->正版,盗版+破解版->盗版 DP:每种情况考虑一遍,递推就行了 注意:开long long */ #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> #include <cmath> using…
In the present world you frequently meet a lot of call numbers and they are going to be longer and longer. You need to remember such a kind of numbers. One method to do it in an easy way is to assign letters to digits as shown in the following pictur…