Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…

题目描述 给定长度为 2n 的数组, 你的任务是将这些数分成 n 对, 例如 (a1, b1), (a2, b2), ..., (an, bn) ,使得从1 到 n 的 min(ai, bi) 总和最大. 示例 1: 输入: [1,4,3,2] 输出: 4 解释: n 等于 2, 最大总和为 4 = min(1, 2) + min(3, 4). 提示: n 是正整数,范围在 [1, 10000]. 数组中的元素范围在 [-10000, 10000]. 思路 分组之后min(ai, bi)的和最大…

561. Array Partition I[easy] Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Inpu…

Question 561. Array Partition I Solution 题目大意是,给的数组大小是2n,把数组分成n组,每组2个元素,每个组取最小值,这样就能得到n个值,怎样分组才能使这n个数相加最小. 思路:有点田忌赛马的意思,肯定最大和第二大一组,取最小值即第二大的数,依次类推...这样就需要排序,隔一个取一个. Java实现: public int arrayPairSum(int[] nums) { Arrays.sort(nums); int total = 0; for (…

LeetCode 80 Remove Duplicates from Sorted Array II [Array/auto] <c++> 给出排序好的一维数组,如果一个元素重复出现的次数大于两次,删除多余的复制,返回删除后数组长度,要求不另开内存空间. C++ 献上自己丑陋无比的代码.相当于自己实现一个带计数器的unique函数 class Solution { public: int removeDuplicates(std::vector<int>& nums) {…

js Array.from & Array.of All In One 数组生成器 Array.from The Array.from() static method creates a new, shallow-copied Array instance from an array-like or iterable object. Array.from()静态方法从类似数组或可迭代的对象中创建一个新的,浅复制的Array实例. Array.from(arrayLike [, mapFn [,…

Array.fill & array padding arr.fill(value[, start[, end]]) https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/fill const log = console.log; const arr = [...new Uint8Array(4)]; //const arr = [1, 2, 3, 4]; log(arr);…

题目描述:两句话发人深思啊.... Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. 感觉题目的大致意思就是把数组分成很多个二元数组,对它…

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say \((a_1, b_1), (a_2, b_2), ..., (a_n, b_n)\) which makes sum of \(min(a_i, b_i)\) for all \(i\) from \(1\) to \(n\) as large as possible. Example 1: Input…

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…

题目要求 Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. 题目分析及思路 题目给出一个含2n个整数的数组,要求拆成n对整数对,使得每个整…

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…

Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Explan…

题目: Given an array of 2n integers, your task is to group these integers into npairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. Example 1: Input: [1,4,3,2] Output: 4 Exp…

原题: Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (a1, b1), (a2, b2), ..., (an, bn) which makes sum of min(ai, bi) for all i from 1 to n as large as possible. 解析: 数组分割1 给一组2n个整数,分割为n组,一组2个数,使min(a,b)…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 排序 日期 题目地址:https://leetcode.com/problems/array-partition-i/#/description 题目描述 Given an array of 2n integers, your task is to group these integers into n pairs of integer, say (…

1.关于json JSON(JavaScript Object Notation) 是一种轻量级的数据交换格式.它基于ECMAScript的一个子集.也可以称为数据集和数组类似,能够存数据! //Array数组 //数组的常用语法如下  数组用中括号<[]存储数据> length数组的长度<数组独有!> var Array=[1,3,5,7,9]; //    数组名 Array<数组/保留字,保留字> //alert(Array.length);    弹出当前  A…

数组的方法 Array.map(); 栗子: var a=[1,2,,3]; var b=a.map( function(value){return value*value} ); alert(b); //[1,4,,9] 参数是一个函数,有返回值 返回值是一个新数组,函数调用原数组的每个元素进行函数格式化,空元素还存在. 数组的Array.every() 每一项都是真才是真;相似于&& Array.some() 某一个是真就是真:类似于|| 当验证一个空数组时: var a=[]; va…

Array.from() lets you convert an "iterable" object (AKA an array-like object) to an array. In this lesson, we go over grabbing DOM nodes and turing them into an array so that we can use methods like Array.filter() and Array.forEach()on them. <…

javascript 没有原生的Distinct功能 . (至少现在还没有)但我们可以通过简单的script 自己实现 . Distinct就是把数组中重复出现2次或以上的值给删除掉,确保数组内每个值都是唯一的 . 我相信大家开始的时候都会和我用同一个方法来处理.那就是开一个新的数组(空),然后 for loop 旧的数组 ,然后复制进去新的数组里面,每次复制进去的时候先检查一篇新数组内是否有了这个值,有了就跳过,没有才加进去 . 代码 :  var old_array = [1, 2, 3,…

原生js封装 function ajaxRequest(type, url, data, callback, failCallBack, header, dataType) { var url_encode = function (str) { return encodeURIComponent(str) .replace(/ /gi, '+') .replace(/~/gi, '%7e') .replace(/'/gi, '%26%2339%3b'); }; type = String(typ…

JavaScript内置对象-1Array(数组) 学习目标 1.掌握任何创建数组 2.掌握数值元素的读和写 3.掌握数组的length属性 如何创建数组 创建数组的基本方式有两种: 1.使用Array构造函数 语法:new Array() 小括号()说明: (1)预先知道数组要保存的项目数量 (2)向Array构造函数中传递数组应包含的项 2.使用数组字量表示法:由一对包数组项的方括号[]表示,多个数组项之间以逗号隔开. 数组元素的读写 读取和设置值时,使用方括号[]并提供相应的索引 说明:索…

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). Find the minimum element. The array may contain duplicates. 思路:有重复元素的时候,不能按I中这么分三类(反例:Input: [3,3,1,3]=>将…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 思路:此时可能存在nums[start]=nums[end]或者nums[start]=n…

// 基于第一个 System.Array 中的关键字,使用每个关键字的 System.IComparable 实现,对两个一维 System.Array // 对象(一个包含关键字,另一个包含对应的项)进行排序. // // 参数: // 第一个: // 一维 System.Array,它包含要排序的关键字. // // 第二个: // 一维 System.Array,它包含与 keysSystem.Array 中的每一个关键字对应的项.- 或 - 如果为null,则只对 keysSystem…

1.微信公众号.微信小程序开发过程中,第三方服务器与微信服务器数据交互,需要进行数据转换,必须用到这两个函数: 分别是xml_to_array.array_to_xml ; /** * 输出xml字符(数组转换成xml) * @param $params 参数名称 * return string 返回组装的xml **/ public function array_to_xml( $params ){ if(!is_array($params)|| count($params) <= 0) {…

Follow up for "Remove Duplicates": What if duplicates are allowed at most twice? For example, Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It doesn'…

int *p[4]------p是一个指针数组,每一个指向一个int型的int (*q)[4]---------q是一个指针,指向int[4]的数组 --> type: int(*)[4] void main(){ // the pointer array char* arry[] = { "hello", "world", "haha" }; ; i < ; i++){ printf("string:%s,address:…