Foreign Exchange Your non-profit organization (iCORE - international Confederation of Revolver Enthusiasts) coordinates a very successful foreign student exchange program. Over the last few years, demand has sky-rocketed and now you need assistance w…
Your non-profitorganization (iCORE - international Confederationof Revolver Enthusiasts) coordinates a very successfulforeign student exchange program. Over the last few years, demand hassky-rocketed and now you need assistance with your task. The pr…
Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Description Your non-profit organization (iCORE - international Confederation of Revolver Enthusiasts) coordinates a very successful foreign student exchange program. Over the…
题目 题目 分析 没什么好说的,字符串拼接一下再放进map.其实可以直接开俩数组排序后对比一下,但是我还是想熟悉熟悉map用法. 呃400ms,有点慢. 代码 #include <bits/stdc++.h> using namespace std; int read(string a) { int ans=0,i=0; while(i<a.length()){ans=(ans<<3)+(ans<<1)+a[i]-'0';i++;} return…
10763 Foreign ExchangeYour non-profit organization (iCORE - international Confederation of Revolver Enthusiasts) coordinatesa very successful foreign student exchange program. Over the last few years, demand hassky-rocketed and now you need assistan…
Foreign Exchange Time Limit:3000MS Memory Limit:0KB 64bit IO Format:%lld & %llu Your non-profit organization (iCORE - international Confederation of Revolver Enthusiasts) coordinates a very successful foreign student exchange program. Over th…
题意:有若干交换生.若干学校,有人希望从A校到B校,有的想从B到C.C到A等等等等.如果有人想从A到B也刚好有人想从B到A,那么可以交换(不允许一对多.多对一).看作后如果有人找不到人交换,那么整个交换计划失败. 代码:(Accepted, 50ms) //UVa10763 - Foreign Exchange #include<cstdio> #include<cstring> int N, a, b,all[1003][1003]; int main() { //freopen…