[LeetCode] Summary Ranges 总结区间】的更多相关文章

Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. Credits:Special thanks to @jianchao.li.fighter for adding this problem and…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
Given a sorted integer array where the range of elements are [0, 99] inclusive, return its missing ranges.For example, given [0, 1, 3, 50, 75], return [“2”, “4->49”, “51->74”, “76->99”] 这道题让我们求缺失区间,跟之前那道Summary Ranges很类似,这道题让我们求缺失的空间,给了一个空间的范围[lo…
Description: Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 确定有序数组的区间 需要注意各种边界细节,每次确定区间之后需要清空. public class Solution { pu…
Given a sorted integer array without duplicates, return the summary of its ranges. For example, given [0,1,2,4,5,7], return ["0->2","4->5","7"]. 思想很简单 逐个比较前后两个数的差值. class Solution { public: vector<string> summaryR…
Given a sorted integer array without duplicates, return the summary of its ranges. Example 1: Input: [0,1,2,4,5,7] Output: ["0->2","4->5","7"] Explanation: 0,1,2 form a continuous range; 4,5 form a continuous range. Exa…
给定一个无重复元素的有序整数数组,返回数组中区间范围的汇总. 示例 1: 输入: [0,1,2,4,5,7]输出: ["0->2","4->5","7"]示例 2: 输入: [0,2,3,4,6,8,9]输出: ["0","2->4","6","8->9"] 详见:https://leetcode.com/problems/summary-ra…
给定一个无重复元素的有序整数数组,返回数组区间范围的汇总. 示例 1: 输入: [0,1,2,4,5,7] 输出: ["0->2","4->5","7"] 解释: 0,1,2 可组成一个连续的区间; 4,5 可组成一个连续的区间. 示例 2: 输入: [0,2,3,4,6,8,9] 输出: ["0","2->4","6","8->9"] 解释:…
题意:给出个有序不重复数列(可能负数),用缩写法记录这个数列. 思路:找每个范围的起始和结束即可. class Solution { public: vector<string> summaryRanges(vector<int>& nums) { if(nums.empty()) return vector<string>(); vector<string> vect; ; i<nums.size(); i++) { int s=nums[i…
Given a sorted integer array nums, where the range of elements are in the inclusive range [lower, upper], return its missing ranges. Example: Input: nums = [0, 1, 3, 50, 75], lower = 0 and upper = 99,Output: ["2", "4->49", "51-…