中国剩余定理 hdu 1573 X问题】的更多相关文章

HDU 1573 X问题 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4857    Accepted Submission(s): 1611 Problem Description 求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0], X mod a[1] = b[1], X mod a[2] = b[2],…
HDU 3579 Hello Kiki Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3107    Accepted Submission(s): 1157 Problem Description One day I was shopping in the supermarket. There was a cashier counti…
X问题 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8354    Accepted Submission(s): 3031 Problem Description 求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0], X mod a[1] = b[1], X mod a[2] = b[2], -, X mo…
扩展中国剩余定理的板子,合并完之后算一下范围内能取几个值即可(记得去掉0) #include<iostream> #include<cstdio> #include<cmath> using namespace std; const int N=15; int T,n,m; long long a[N],b[N],A,B,x,y,d; bool fl; void exgcd(long long a,long long b,long long &d,long lo…
http://acm.hdu.edu.cn/showproblem.php?pid=1573 X问题 Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4439    Accepted Submission(s): 1435 Problem Description 求在小于等于N的正整数中有多少个X满足:X mod a[0] = b[0],…
Lucky7 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5768 Description When ?? was born, seven crows flew in and stopped beside him. In its childhood, ?? had been unfortunately fall into the sea. While it was dying, seven dolphins arched its body an…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5768 给你n个同余方程组,然后给你l,r,问你l,r中有多少数%7=0且%ai != bi. 比较明显的中国剩余定理+容斥,容斥的时候每次要加上个(%7=0)这一组. 中间会爆longlong,所以在其中加上个快速乘法(类似快速幂).因为普通的a*b是直接a个b相加,很可能会爆.但是你可以将b拆分为二进制来加a,这样又快又可以防爆. //#pragma comment(linker, "/STACK…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5768 题目大意: T组数据,求L~R中满足:1.是7的倍数,2.对n个素数有 %pi!=ai  的数的个数. 题目思路: [中国剩余定理][容斥原理][快速乘法][数论] 因为都是素数所以两两互素,满足中国剩余定理的条件. 把7加到素数中,a=0,这样就变成解n+1个同余方程的通解(最小解).之后算L~R中有多少解. 但是由于中国剩余定理的条件是同时成立的,而题目是或的关系,所以要用容斥原理叠加删…
题目链接: http://poj.org/problem?id=1006 http://acm.hdu.edu.cn/showproblem.php?pid=1370 题目大意: (X+d)%23=a1,(X+d)%28=a2,(X+d)%33=a3,给定a1,a2,a3,d,求最小的X. 题目思路: [中国剩余定理] 23,28,33互素,可以套中国剩余定理. 也可以直接手算逆元. 33×28×a模23的逆元为8,则33×28×8=5544: 23×33×b模28的逆元为19,则23×33×1…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4767 题意:求集合{1, 2, 3, ..., n}有多少种划分情况bell[n],最后结果bell[n] mod 95041567. 分析:首先了解三个概念:贝尔数   第二类斯特灵数   中国剩余定理 贝尔数是指基数为n的集合的划分方法的数目. 贝尔数适合递推公式: 每个贝尔数都是"第二类Stirling数"的和 贝尔数满足两个公式:(p为质数)             1) B[n+…