题目描述 输入一个链表,输出该链表中倒数第k个结点 # -*- coding:utf-8 -*- # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def FindKthToTail(self, head, k): # write code here #遍历一次链表获得链表长度,再次遍历链表,至n-k+1出输出 if head == None or k <= 0…
输入一个链表,输出该链表中倒数第K个结点 public class ListNode { int val; ListNode next = null; ListNode(int val) { this.val = val; } public class Solution { public ListNode FindKthToTail(ListNode head,int k) { ListNode p = head; ListNode pre = head; int a =k; int count…