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Java [Leetcode 42]Trapping Rain Water

题目描述: Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. 解题思路: 思路一:开辟两个数组空间,逐个遍历数组,找出该位置左边的最大值…

leetcode#42 Trapping rain water的五种解法详解

leetcode#42 Trapping rain water 这道题十分有意思,可以用很多方法做出来,每种方法的思想都值得让人细细体会. 42. Trapping Rain WaterGiven n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For ex…

[array] leetcode - 42. Trapping Rain Water - Hard

leetcode - 42. Trapping Rain Water - Hard descrition Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1],…

LeetCode 42. Trapping Rain Water 【两种解法】（python排序遍历，C++ STL map存索引，时间复杂度O（nlogn））

LeetCode 42. Trapping Rain Water Python解法 解题思路: 本思路需找到最高点左右遍历,时间复杂度O(nlogn),以下为向左遍历的过程. 将每一个点的高度和索引存成一个元组 (val, idx) 找到最高的点(可能有多个,任取一个),记为 (now_val, now_idx). 向左找第一个val不大于now_val的点(left_val, left_idx). 以left_val作为水平面,用height[left_val+1, now_val-1]中每一…

LeetCode - 42. Trapping Rain Water

42. Trapping Rain Water Problem's Link ---------------------------------------------------------------------------- Mean: 在坐标上给你一些竖直放置的条形积木,问你这个积木能够容纳多少液体. analyse: 首先找出最高的积木,然后从前往后一直扫到最高积木,从后往前一直扫到最高积木,两部分体积相加即可. Time complexity: O(N) view code ;  …

[LeetCode] 42. Trapping Rain Water 收集雨水

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of…

leetCode 42.Trapping Rain Water(凹槽的雨水) 解题思路和方法

Trapping Rain Water Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example,  Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevation ma…

[LeetCode] 42. Trapping Rain Water 解题思路

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. For example, Given [0,1,0,2,1,0,1,3,2,1,2,1], return 6. The above elevation map is represented by a…

[leetcode]42. Trapping Rain Water雨水积水问题

Given n non-negative integers representing an elevation map where the width of each bar is 1, compute how much water it is able to trap after raining. The above elevation map is represented by array [0,1,0,2,1,0,1,3,2,1,2,1]. In this case, 6 units of…

LeetCode 42 Trapping Rain Water（积水体积）

题目链接: https://leetcode.com/problems/trapping-rain-water/?tab=Description   Problem: 根据所给数组的值,按照上图的示意图.求解积水最大体积.     首先对所给数组进行遍历操作,求出最大高度所对应的下标为maxIndex   之后从左向右进行遍历,设置左边高度为leftMax 并初始化为 height[0],从i==1到i==maxIndex进行遍历.不断更新water,以及leftMax     当height[…