LCIS /* 1423 */ #include <cstdio> #include <cstring> #include <cstdlib> #define MAXN 505 int a[MAXN]; int b[MAXN]; int c[MAXN]; int n, m; int ans; int max(int a, int b) { return a>b ? a:b; } void solve() { int i, j, k; memset(c, , siz…

HDOJ 1423 Greatest Common Increasing Subsequence [DP][最长公共上升子序列] Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8768 Accepted Submission(s): 2831 Problem Description This is a problem from ZOJ 24…

HDU 1423 Greatest Common Increasing Subsequence(最长公共上升LCIS) http://acm.hdu.edu.cn/showproblem.php?pid=1423 题意: 给你两个数字组成的串a和b,要你求出它们的最长公共严格递增子序列的长度(LCIS). 分析: 首先我们令f[i][j]==x表示是a串的前i个字符与b串的前j个字符构成的且以b[j]结尾的LCIS长度. 当a[i]!=b[j]时:        f[i][j]=f[i-1][j…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=1423 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28195#problem/F Greatest Common Increasing Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total…

题目地址:http://acm.hdu.edu.cn/showproblem.php?pid=1423 Problem Description This is a problem from ZOJ 2432.To make it easyer,you just need output the length of the subsequence.   Input Each sequence is described with M - its length (1 <= M <= 500) and…

题目链接: 题目 Greatest Common Increasing Subsequence Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) 问题描述 This is a problem from ZOJ 2432.To make it easyer,you just need output the length of the subsequence. 输入 Each sequen…

Greatest Common Increasing Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3460    Accepted Submission(s): 1092 Problem Description This is a problem from ZOJ 2432.To make it easyer,…

Greatest Common Increasing Subsequenc Problem Description This is a problem from ZOJ 2432.To make it easyer,you just need output the length of the subsequence.   Input Each sequence is described with M - its length (1 <= M <= 500) and M integer numb…

Greatest Common Increasing Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5444    Accepted Submission(s): 1755 Problem Description This is a problem from ZOJ 2432.To make it easyer,…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1423 思路分析:[问题定义]给定两个序列A[0, 1,..., m]和B[0, 1, ..., n],要求这两个序列的最长公共上升子序列: 该问题为动态规划问题,可以采用与求最长公共子序列与最长上升子序列相同的思想来思考求出动态规划方程; 定义状态dp[i][j] 为序列A的前 i 个数字与序列B 的最长公共上升子序列,且该最长公共上升子序列以序列B的第 j 个数字为最后一个数字: 则可以推导出动态…