Problem:Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longe…

Longest Substring Without Repeating Characters Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the lengt…

题目描述 Given a string, find the length of the longest substring without repeating characters. Example 1 Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2 Input: "bbbbb" Output: 1 Expl…

LeetCode 第 3 题(Longest Substring Without Repeating Characters) Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "b…

问题简介:求给定字符串中最长的字符不重复的字符串的长度 问题详解: 给定一个字符串,寻找给定字符串中包含的最长的字符不重复的字符串的长度 注:答案必须是子字符串,不是子序列 是连续的字符不重复的字符串,不是所有不重复字符 举例: 1. 输入: “abcabcbb” 输出: 3 解释: 结果是 “abc”, 长度是 3 2. 输入: “bbbbb” 输出: 1 解释: 结果是 “b”,长度是 1 3. 输入: “pwwkew” 输出: 3 解释: 结果是 “wke”,长度是 3 JAVA 实现方法…

题目等级:Medium 题目描述:   Given a string, find the length of the longest substring without repeating characters.   Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3.   Example 2: Input: "bbbbb…

题目如下: Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb" Output: 3 Explanation: The answer is "abc", with the length of 3. Example 2: Input: "bbbbb" Output: 1 E…

Given a string, find the length of the longest substring without repeating characters. Examples: Given "abcabcbb", the answer is "abc", which the length is 3. Given "bbbbb", the answer is "b", with the length of 1.…

题目: Given a string, find the length of the longest substring without repeating characters. For example, the longest substring without repeating letters for "abcabcbb" is "abc", which the length is 3. For "bbbbb" the longest s…

HashMap的应用可以提高查找的速度,键key,值value的使用拜托了传统数组的遍历查找方式,对于判断一个字符或者字符串是否已经存在的问题可以非常好的解决.而本题需要解决的问题就是判断新遍历到的字符是否已经存在于左left,右right,字符构成的子串之中. 解题思路:设置一个left作为子串的最左边的字符位置坐标,right不断向右遍历,并对每次遍历得到的字符进行判断,max作为最大的没有重复字符的子串长度.对于right遍历得到的新的字符,有两种情况: 一:在Hash表中没有,此时该字符…