Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0. Example 1: Input: 22 Output: 2 Explanation: 22 in binary is 0b10110. In the…

给定一个正整数 N,找到并返回 N 的二进制表示中两个连续的 1 之间的最长距离. 如果没有两个连续的 1,返回 0 . 示例 1: 输入:22 输出:2 解释: 22 的二进制是 0b10110 . 在 22 的二进制表示中,有三个 1,组成两对连续的 1 . 第一对连续的 1 中,两个 1 之间的距离为 2 . 第二对连续的 1 中,两个 1 之间的距离为 1 . 答案取两个距离之中最大的,也就是 2 . 示例 2: 输入:5 输出:2 解释: 5 的二进制是 0b101 . 示例 3: 输…

中文标题[二进制空白] 英文描述 A binary gap within a positive integer N is any maximal sequence of consecutive zeros that is surrounded by ones at both ends in the binary representation of N. For example, number 9 has binary representation 1001 and contains a bina…

[067-Add Binary(二进制加法)] [LeetCode-面试算法经典-Java实现][全部题目文件夹索引] 原题 Given two binary strings, return their sum (also a binary string). For example, a = "11" b = "1" Return "100" 题目大意 给定两个二进制的字符串,返回它们的和,也是二进行制字符串. 解题思路 先将相应的两个二进制字符…

problem 868. Binary Gap solution1: class Solution { public: int binaryGap(int N) { ; vector<int> pos; ; ) { ==) pos.push_back(k); k++; N >>=;//errr... } ; i<pos.size(); ++i) { res = max(res, pos[i]-pos[i-]); } return res; } }; solution2: cl…

Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0. Example 1: Input: 22 Output: 2 Explanation: 22 in binary is 0b10110. In the…

Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written in bin…

［抄题］: Given two integers L and R, find the count of numbers in the range [L, R] (inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written…

题目要求 Given a positive integer N, find and return the longest distance between two consecutive 1's in the binary representation of N. If there aren't two consecutive 1's, return 0. 题目分析及思路 给定一个正整数,返回该数二进制形式中连续两个1的最长间隔.若是没有连续的两个1,则返回0.可将该数转成二进制形式,得到的结果…

Given two binary strings, return their sum (also a binary string). For example,a = "11"b = "1"Return "100". 简单的二进制相加而已,只不过传入的参数是字符串而已.为了方便,先将string  reverse了一下,代码如下: class Solution { public: string addBinary(string a, string…