Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example:        Input: 1->2->4, 1->3->4              Output: 1->1->2->3->4->4 解决思路:最简单…

作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 个人公众号:负雪明烛 本文关键词:合并,有序链表,递归,迭代,题解,leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 迭代 Python解法 C++解法 Java解法 递归 日期 题目地址:https://leetcode.com/problems/merge-two-sorted-lists/ 题目描述 Merge two sorted…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. Example: Input: [   1->4->5,   1->3->4,   2->6 ] Output: 1->1->2->3->4->4->5->6 要合并K个排好序的链表,我用的方法是用一个优先队列每次存K个元素在队列中,根据优…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 list顺序合并就可以了 /** * Definitio…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. 题意:合并两个排好的链表并返回新的链表. 可以使用归并排序,从两链表的表头,取出结点,比较两值,将较小的放在新链表中.如1->3->5->6和2->4->7->8,先将1放入新链表,然后将3…

题目: Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 分析: 将两个有序链表合并为一个新的有序链表并返…

这道题是LeetCode里的第21道题. 题目描述: 将两个有序链表合并为一个新的有序链表并返回.新链表是通过拼接给定的两个链表的所有节点组成的. 示例: 输入:1->2->4, 1->3->4 输出:1->1->2->3->4->4 这道题需要考虑的地方挺多的,首先是头节点的处理,还有尾节点的链接问题.对于头节点,我的想法是先对 l1, l2 的值进行比较,然后把 l1 指向头节点值小的,这样保证了 l1 绝对小于等于 l2,也就是说头节点的链接问题…

Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.Example:Input: 1->2->4, 1->3->4Output: 1->1->2->3->4->4详见:https://leetcode.com/problems…

描述: 合并两个有序链表. 解决: ListNode* mergeTwoLists(ListNode* l1, ListNode* l2) { if (!l1) return l2; if (!l2) return l1; if (!l1 && !l2) return NULL; ListNode* ret = ); ListNode* now = ret; while (l1 || l2) { if (!l1) { now->next = l2; break; } else if…

Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity. 这道题让我们合并k个有序链表,之前我们做过一道Merge Two Sorted Lists 混合插入有序链表,是混合插入两个有序链表.这道题增加了难度,变成合并k个有序链表了,但是不管合并几个,基本还是要两两合并.那么我们首先考虑的方法是能不能利用之前那道题的解法来解答此题.答案是肯定的,但是需要修改…