要求:Given a binary tree, flatten it to a linked list in-place.将二叉树转化为平坦序列的树.比如: 结题思路: 该题有个提示,转化后的树的序列正好是二叉树前序遍历所得到的序列,所以,该题第一个思路就是利用前序遍历的方式来做. 第二个思路:我们可以利用递归的思路,先对根节点进行处理,将root的左子树放到右子树,在将左子树中的最右端节点“嫁接”到右子树,接着上面得到的子树.接下来在用同样的方法处理当前二叉树的下一个节点.看下面一个图,即可明…
Given two binary trees, write a function to check if they are the same or not. Two binary trees are considered the same if they are structurally identical and the nodes have the same value. Example 1: Input: / \ / \ [,,], [,,] Output: true Example 2:…
#include <iostream> using namespace std; struct Tree { int data; Tree *lchild; Tree *rchild; }tree; Tree *Create(int a1[],int b1[],int n) { int k; ) return NULL; ]; Tree *bt=(Tree *)malloc(sizeof(Tree)); bt->data=root; ;k<n;k++) { if(b1[k]==ro…
