题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1002 A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 230247    Accepted Submission(s): 44185 Problem Description I have a very sim…

A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 315214    Accepted Submission(s): 61139 Problem Description I have a very simple problem for you. Given two integers A and B, you…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1002 A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 409136    Accepted Submission(s): 79277 Problem Description I have a very si…

目录 题目地址 题干 代码和解释 参考 题目地址 hdu1002 题干 代码和解释 由题意这是一个涉及到大数的加法问题.去看了一眼大数加法的方法感觉头很大,然后突然发现Java可以流氓解决大数问题,毅然为之. import java.util.Scanner; import java.math.BigInteger; public class Main{ public static void main(String args[]){ BigInteger a,b; int T; int n=1;…

杭电ACM(1002)大数相加 A + B Problem II Problem DescriptionI have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B. InputThe first line of the input contains an integer T(1<=T<=20) which means the number…

A + B Problem II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 308484    Accepted Submission(s): 59635 Problem Description I have a very simple problem for you. Given two integers A and B, yo…

Problem Description I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B. Input The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines fol…

题目描述: Input The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should n…

一直格式错误,不想改了,没A #include <iostream> #include <stdio.h> #include <string.h> #include <stdlib.h> using namespace std; int main() { ; scanf("%d",&T); ],b[]; ],tb[]; getchar(); while(T--) { K++; scanf("%s%s",a,b)…

一个出栈有多少种顺序的问题.一般都知道是Catalan数了. 问题是这个Catalan数非常大,故此须要使用高精度计算. 并且打表会速度快非常多.打表公式要熟记: Catalan数公式 Cn=C(2n,n) / (n+1); 递推公式 C(n ) = C(n-1)*(4*n-2) / (n+1) 高精度乘以一个整数和高精度除以一个整数的知识.这样还是使用整数数组比較好计算,假设使用string那么就不太好计算了,由于整数也可能是多位的. const int MAX_N = 101; short…