原题地址: 344 Reverse String: https://leetcode.com/problems/reverse-string/description/ 541 Reverse String II: https://leetcode.com/problems/reverse-string-ii/description/ 题目&&解法: 1.Reverse String: Write a function that takes a string as input and ret…

344. Reverse String 最基础的旋转字符串 class Solution { public: void reverseString(vector<char>& s) { if(s.empty()) return; ; ; while(start < end){ char tmp = s[end]; s[end] = s[start]; s[start] = tmp; start++; end--; } return; } }; 541. Reverse Strin…

package leadcode; /** * 541. Reverse String II * Easy * 199 * 575 * * * Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters lef…

problem 541. Reverse String II 题意: 给定一个字符串,每隔k个字符翻转这k个字符,剩余的小于k个则全部翻转,否则还是只翻转剩余的前k个字符. solution1: class Solution { public: string reverseStr(string s, int k) { int n = s.size(); int cnt = n / k; ; i<=cnt; i++) { ==) { if(i*k+k<n) reverse(s.begin()+i…

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…

static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }(); class Solution { public: string reverseStr(string s, int k) { int len=s.length(); auto p=s.begin(); int i; *k) reverse(p+i-k,p+i); i-=*k; if(len==i) return s; else if(len-…

［抄题］: Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than…

给定一个字符串和一个整数 k,你需要对从字符串开头算起的每个 2k 个字符的前k个字符进行反转.如果剩余少于 k 个字符,则将剩余的所有全部反转.如果有小于 2k 但大于或等于 k 个字符,则反转前 k 个字符,并将剩余的字符保持原样.示例:输入: s = "abcdefg", k = 2输出: "bacdfeg"要求:    1.该字符串只包含小写的英文字母.    2.给定字符串的长度和 k 在[1, 10000]范围内.详见:https://leetcode.…

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 题目地址:https://leetcode.com/problems/reverse-string-ii/#/description 题目描述 Given a string and an integer k, you need to reverse the first k characters for every…

541. 反转字符串 II 541. Reverse String II…

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…

原题链接在这里:https://leetcode.com/problems/reverse-string-ii/#/description 题目: Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters l…

Given a string and an integer k, you need to reverse the first k characters for every 2k characters counting from the start of the string. If there are less than k characters left, reverse all of them. If there are less than 2k but greater than or eq…

这是悦乐书的第256次更新,第269篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第123题(顺位题号是541).给定一个字符串和一个整数k,你需要反转从字符串开头算起的每2k个字符的前k个字符. 如果剩下少于k个字符,则反转所有字符. 如果小于2k但大于等于k个字符,则反转前k个字符,剩下的字符不变.例如: 输入:s ="abcdefg",k = 2 输出:"bacdfeg" 注意: 该字符串仅包含小写的英文字母. 给定字符串的长度和…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3951 访问. 给定一个字符串和一个整数 k,你需要对从字符串开头算起的每个 2k 个字符的前k个字符进行反转.如果剩余少于 k 个字符,则将剩余的所有全部反转.如果有小于 2k 但大于或等于 k 个字符,则反转前 k 个字符,并将剩余的字符保持原样. 输入: s = "abcdefg", k = 2 输出: "bacdfeg" 要求…

Write a function that takes a string as input and returns the string reversed. Example: Given s = "hello", return "olleh". 这道题没什么难度,直接从两头往中间走,同时交换两边的字符即可,参见代码如下: 解法一: class Solution { public: string reverseString(string s) { , right =…

原题链接在这里:https://leetcode.com/problems/reverse-string/ 题目: Write a function that takes a string as input and returns the string reversed. Example:Given s = "hello", return "olleh". 题解: Reverse string是常见题, string在Java中是primitive类型, 一旦生成不…

［抄题］: [暴力解法]: 时间分析: 空间分析: ［奇葩输出条件］: ［奇葩corner case］: ［思维问题］: 还停留在 i < len / 2的阶段,不行,应该是指针对撞问题了 ［一句话思路］: 先要把字符串转成数组,再转回来,数据结构白学了? ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 用.tochararray转成字符串数组,顾名思义了 ［二刷］: ［三刷］: ［四刷］: ［五刷］: [五分钟肉眼deb…

Write a function that reverses a string. The input string is given as an array of characters char[]. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. You may assume all the…

Reverse Words in a String I Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Have you met this question in a real interview? Yes Clarification What constitutes a…

Given an input string, reverse the string word by word. A word is defined as a sequence of non-space characters.The input string does not contain leading or trailing spaces and the words are always separated by a single space.For example,Given s = "t…

541. 反转字符串 II 题目链接 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/reverse-string-ii 著作权归领扣网络所有.商业转载请联系官方授权,非商业转载请注明出处. 题目描述 给定一个字符串 s 和一个整数 k,从字符串开头算起,每 2k 个字符反转前 k 个字符. 如果剩余字符少于 k 个,则将剩余字符全部反转. 如果剩余字符小于 2k 但大于或等于 k 个,则反转前 k 个字符,其余字符保持原样. 示例 1:…

第一题344.反转字符串 编写一个函数,其作用是将输入的字符串反转过来.输入字符串以字符数组 s 的形式给出. 不要给另外的数组分配额外的空间,你必须原地修改输入数组.使用 O(1) 的额外空间解决这一问题. ψ(｀∇´)ψ 我的思路 取到字符串的中点,依次交换前后两部分的位置 package string; public class ReverseString { public static void reverseString(char[] s) { char temp; for (int…

541. 反转字符串 II 给定一个字符串和一个整数 k,你需要对从字符串开头算起的每个 2k 个字符的前k个字符进行反转.如果剩余少于 k 个字符,则将剩余的所有全部反转.如果有小于 2k 但大于或等于 k 个字符,则反转前 k 个字符,并将剩余的字符保持原样. 示例: 输入: s = "abcdefg", k = 2 输出: "bacdfeg" 要求: 该字符串只包含小写的英文字母. 给定字符串的长度和 k 在[1, 10000]范围内. PS: 暴力 欢迎评论…

下面是今天写的几道题: 292. Nim Game You are playing the following Nim Game with your friend: There is a heap of stones on the table, each time one of you take turns to remove 1 to 3 stones. The one who removes the last stone will be the winner. You will take t…

1.2 Implement a function void reverse(char *str) in C or C++ which reverses a null-terminated string. 这道题让我们用C++或C语言来翻转一个字符串,不算一道难题,在之前那道Reverse Words in a String 翻转字符串中的单词中用到了这个函数,跟那道题比起来,这题算简单的了.C语言的版本要比C++的稍微复杂一些,应为string类集成了很多有用的功能,比如得到字符串的长度,用下标…

344. Reverse String Write a function that takes a string as input and returns the string reversed. Example: Given s = "hello", return "olleh". 题目大意: 字符串倒置. 解题方法: 第一个字符与最后一个非空字符对换. 注意事项: 1.字符串最后一个字符是空字符. C++代码: 1.不良代码: class Solution {…

344. Reverse String /** * @param {string} s * @return {string} */ var reverseString = function(s) { return s.split("").reverse().join(""); }; 292. Nim Game 尼姆游戏还是很有意思的,这题有很多地方可以深入理解 /** * @param {number} n * @return {boolean} */ var ca…