104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB PROBLEM You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least a…
104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB 问题: 你想要将你的花窗安排得最具美感.有F束花,每一束花都不一样,至少有F个按顺序排成一行的花瓶.花瓶从左到右,依次编号1-V.而花放置的位置是可以改变的,花依次编号1到F.花的序号有一个特征,即是序号决定了花束出现在花瓶里的顺序.例如,有两束花编号i和j,满足i<j,那么i所在的花瓶一定要在j所在花瓶的左边,即是i…
104. Little shop of flowers time limit per test: 0.25 sec. memory limit per test: 4096 KB PROBLEM You want to arrange the window of your flower shop in a most pleasant way. You have F bunches of flowers, each being of a different kind, and at least a…
题意 每个花按序号顺序放到窗口,不同窗口可有不同观赏值,所有花都要放上去,求最大观赏值和花的位置. 分析 dp,dp[i][j]表示前i朵花最后一朵在j位置的最大总观赏值. dp[i][j]=max(dp[i-1][k]+f[i][j]) 代码 #include<cstdio> #include<algorithm> using namespace std; const int N=105; int n,w,ans=-99999; int dp[N][N],f[N][N],last…
经典dp问题,花店橱窗布置,不再多说,上代码 #include <cstdio> #include <cstring> #include <iostream> #include <cstdlib> #include <algorithm> #define N 150 #define inf 0x7f7f7f7f using namespace std; int n, m; int val[N][N], f[N][N]; int fa[N][N];…
130. Circle time limit per test: 0.25 sec. memory limit per test: 4096 KB On a circle border there are 2k different points A1, A2, ..., A2k, located contiguously. These points connect k chords so that each of points A1, A2, ..., A2k is the end point…
