题目链接:http://poj.org/problem?id=2408 World-renowned Prof. A. N. Agram's current research deals with large anagram groups. He has just found a new application for his theory on the distribution of characters in English language texts. Given such a text…
Description World-renowned Prof. A. N. Agram's current research deals with large anagram groups. He has just found a new application for his theory on the distribution of characters in English language texts. Given such a text, you are to find the la…
容错声明: ①题目选自https://acm.ecnu.edu.cn/,不再检查题目删改情况 ②所有代码仅代表个人AC提交,不保证解法无误 E0001 A+B Problem First AC: 2017-10-13 Latest Modification: 2018-02-28 #include<bits/stdc++.h> using namespace std; int a,b; int main() { cin>>a>>b; cout<<…
Two strings X and Y are similar if we can swap two letters (in different positions) of X, so that it equals Y. For example, "tars" and "rats" are similar (swapping at positions 0 and 2), and "rats" and "arts" are si…
Two strings X and Y are similar if we can swap two letters (in different positions) of X, so that it equals Y. For example, "tars" and "rats" are similar (swapping at positions 0 and 2), and "rats" and "arts" are si…
You are given an array A of strings. Two strings S and T are special-equivalent if after any number of moves, S == T. A move consists of choosing two indices i and j with i % 2 == j % 2, and swapping S[i] with S[j]. Now, a group of special-equivalent…
这是悦乐书的第344次更新,第368篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第209题(顺位题号是893). You are given an array A of strings. Two strings S and T are special-equivalent if after any number of moves, S == T. A move consists of choosing two indices i and j with i % 2…
题目描述 假设给定两个字符串 s 和 t, 让我们写出一个方法来判断这两个字符串是否是字母异位词? 字母异位词就是,两个字符串中含有字母的个数和数量都一样,比如: Example 1: Input: s = "anagram", t = "nagaram" Output: true 字符串 s 和 t 含有的字母以及字母的数量都一致,所以是 True. Example 2: Input: s = "rat", t = "car"…
You are given an array A of strings. Two strings S and T are special-equivalent if after any number of moves, S == T. A move consists of choosing two indices i and jwith i % 2 == j % 2, and swapping S[i] with S[j]. Now, a group of special-equivalent…
［抄题］: Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A. We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at…
/* 思路是判断26个字符在两个字符串中出现的次数是不是都一样,如果一样就返回true. 记住这个方法 */ if (s.length()!=t.length()) return false; int[] words = new int[26]; for (int i = 0; i < s.length(); i++) { words[s.charAt(i)-'a']++; words[t.charAt(i)-'a']--; } for (int i = 0; i < 26; i++) { i…
1. palindrome-partitioning Given a string s, partition s such that every substring of the partition is a palindrome. Return all possible palindrome partitioning of s. For example, given s ="aab",Return [ ["aa","b"], ["a&…
StackOverFlow排错翻译 - Python字符串替换: How do I replace everything between two strings without replacing the strings? 原创连接: Python字符串替换 问题: Python:如何将两字符串之间的内容替换掉? I have this string(问题源码): str = ''' // DO NOT REPLACE ME // Anything might be here. Numbers…
Given a string s and a non-empty string p, find all the start indices of p's anagrams in s. Strings consists of lowercase English letters only and the length of both strings s and p will not be larger than 20,100. The order of output does not matter.…
Given two strings s and t, write a function to determine if t is an anagram of s. For example, s = "anagram", t = "nagaram", return true. s = "rat", t = "car", return false. Note: You may assume the string contains…
参考网络文章,个人工作总结 题记:一般对字符串的操作有以下几种:求长度,截取字符串,拼接字符串,找字符串中某个字符的索引 1 expr 命令 1.1 定义 man 手册 Print the value of EXPRESSION to standard output. A blank line below separates increasing precedence groups. EXPRESSION may be: ARG1 | ARG2 ARG1 , otherwise ARG2 ARG…
Given two strings s and t, write a function to determine if t is an anagram of s. For example,s = "anagram", t = "nagaram", return true.s = "rat", t = "car", return false. Note:You may assume the string contains onl…
