Description 给出长度分别为1~n的珠子,长度为i的珠子有a[i]种,每种珠子有无限个,问用这些珠子串成长度为n的链有多少种方案 题解: dp[i]表示组合成包含i个贝壳的项链的总方案数 转移:dp[i]=Σdp[i-j]*a[j](1<=j<=i) #include <bits/stdc++.h> using namespace std; #define dob complex<double> #define rint register int #defin…
Description Perhaps the sea‘s definition of a shell is the pearl. However, in my view, a shell necklace with n beautiful shells contains the most sincere feeling for my best lover Arrietty, but even that is not enough. Suppose the shell necklace is a…
Perhaps the sea‘s definition of a shell is the pearl. However, in my view, a shell necklace with n beautiful shells contains the most sincere feeling for my best lover Arrietty, but even that is not enough. Suppose the shell necklace is a sequence of…
Shell Necklace Problem Description Perhaps the sea‘s definition of a shell is the pearl. However, in my view, a shell necklace with n beautiful shells contains the most sincere feeling for my best lover Arrietty, but even that is not enough. Suppose…
题目 Source http://acm.hdu.edu.cn/showproblem.php?pid=5730 Description Perhaps the sea‘s definition of a shell is the pearl. However, in my view, a shell necklace with n beautiful shells contains the most sincere feeling for my best lover Arrietty, but…
Shell Necklace Time Limit: 16000/8000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 534 Accepted Submission(s): 227 Problem Description Perhaps the sea‘s definition of a shell is the pearl. However, in my view,…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=2660 Accepted Necklace Description I have N precious stones, and plan to use K of them to make a necklace for my mother, but she won't accept a necklace which is too heavy. Given the value and the weight…
Problem Description I have N precious stones, and plan to use K of them to make a necklace for my mother, but she won't accept a necklace which is too heavy. Given the value and the weight of each precious stone, please help me find out the most valu…
Accepted Necklace Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2474 Accepted Submission(s): 973 Problem Description I have N precious stones, and plan to use K of them to make a necklace f…
Problem Description Little Q wants to buy a necklace for his girlfriend. Necklaces are single strings composed of multiple red and blue beads. Little Q desperately wants to impress his girlfriend, he knows that she will like the necklace only if for…
重温了这道cdq+FFT 讲白了就是不断对 dp[l~mid] 和 sh[1~r] 进行fft 得到 dp[mid+1~r] #include<bits/stdc++.h> using namespace std; typedef long long ll; const int MAXN = 1e5+5; const int MOD = 313; int N; int sh[MAXN], dp[MAXN]; int ans; /****************FFT*************/…
矩阵快速幂. 因为任意素数长度都要满足,所以$3$必须满足,$3$一旦满足,其余的肯定满足,也就是说只要考虑字符串末尾两位即可,$dp$一下就可以算方案数了.$n$较大,可以矩阵加速. #include <bits/stdc++.h> using namespace std; ; const long long inf=1e18; int T; long long n; struct Matrix { ][]; int R, C; Matrix operator*(Matrix b); };…
