How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 46694    Accepted Submission(s): 23319 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Description: Today is Ignatius' birthda…

题目大意: 有一个人要过生日了,请他的朋友来吃饭,但是他的朋友互相认识的才能坐在一起,朋友的编号从1 ~ n,输入的两个数代表着这两个人互相认识(如果1和2认识,2和3认识,那么1和3也就认识了).问需要多少桌子. 思路: 并查集的基础题目,pre数组存的是父节点的值,root数组代表是否为根节点.最后统计根节点的数量就可以了~~~~~ #include <iostream> #include <cstdio> #include <cstring> #include &…

-----------刷点水题练习java------------- 题意:给定N点,M边的无向图,问有多少个连通块. 思路:可以搜索;  可以并查集.这里用并查集练习java的数组使用,ans=N,合并一个连通块ans--: 以及函数的调用: 经验1:C++声明数组是int fa[1024]:而java则是int[] fa=new int[1024]; 经验2:不加static是非静态函数,访问需要new出该类的对象来调用,加上static是静态函数 可直接访问或者通过类名访问. import…

How Many Tables 题目链接: http://acm.hust.edu.cn/vjudge/contest/123393#problem/C Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that…

题目链接:hdu1213 赤裸裸的并查集.....水题一个.... #include<stdio.h> #include<string.h> #include<algorithm> #include<queue> #define MAXN 10 using namespace std; int father[1005]; void build(int n) { for(int i = 0 ; i <= n ; i ++) father[i] = i;…

题目传送门:HDU--1213 //题意:ignatius过生日,客人来到,他想知道他需要准备多少张桌子.然而一张桌子上面只能坐上相互熟悉的人, //其中熟悉可定义成为A与B认识,B与C认识,我们就说A,B,C相互熟悉 .例如A与B熟悉and B与C熟悉,D与E熟悉,此时至少需要两张桌子. //输入:t表示样例个数,n表示朋友个数,朋友从1到n编号,m表示已知相互了解的对数,接着m行.每行表示相互熟悉的编号 //输出:至少需要准备的桌子个数 //刚学并查集!简单的并查集模板应用. #includ…

How Many Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 31632 Accepted Submission(s): 15706 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner ti…

J - How Many Tables Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You…

Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay…

How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at…

题目链接:http://icpc.njust.edu.cn/Problem/Hdu/1213/ 并查集是一种支持合并与查找的数据结构,在森林中进行操作,加上路径压缩,合并和查找的时间复杂度几乎都是常数.并查集最基础的作用就是建立不同的点之间的所谓的“关系”,并且查询两者是否有关系.并查集的一个特点是向量型关系传递性,比如A->B B->C,则有A->C,是不是特别像向量之间的传递?在很多时候并查集的应用都涉及到了这个性质.并查集的代码可比线段树主席树友好一点orz hdu1213板题,代…

题意:有 n 个朋友,他们可能相互认识,A 认识 B,B 认识 C,则 ABC 相互认识,现在给出他们的认识情况,相互认识的人坐一桌,否则需要分开坐,问至少需要多少桌. 其实就是问并查集的个数,在初始情况下一人一个并查集,共 n 个,每次合并操作会减少一个并查集,所以只要每次合并时计数减一下就行,全部合并完之后就可以输出剩余并查集个数了. #include<iostream> #include<cstdio> #include<cstring> using namesp…

什么也不用说,并查集裸题,直接盲敲即可. #include <iostream> #include <cstring> #include <cstdlib> #include <cstdio> #include <cctype> #include <cmath> #include <algorithm> #include <numeric> using namespace std; ]; int getFath…

http://acm.hdu.edu.cn/showproblem.php?pid=1213 题意: 这个问题的一个重要规则是,如果我告诉你A知道B,B知道C,这意味着A,B,C知道对方,所以他们可以留在一个桌子. 例如:如果我告诉你A知道B,B知道C,D知道E,所以A,B,C可以留在一个桌子中,D,E必须留在另一个桌子中.所以Ignatius至少需要2个桌子. 思路: 并查集模板题. #include<iostream> using namespace std; ]; int find(in…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=1213 题意 给出N个人 M对关系 找出共有几对连通块 思路 并查集 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #include <cmath> #include <climits> #include <ctime&g…

传送门 Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to…

How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 17411    Accepted Submission(s): 8527点我 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's din…

Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want…

Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay with strang…

点击打开链接 Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other, and all the friends do not want to stay with…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13787    Accepted Submission(s): 6760 Problem Description Today is Ignatius' b…

How Many Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17892 Accepted Submission(s): 8794 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner tim…

解题思路:和畅通工程类似,问最后还剩下几个不连通的区域. How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15086    Accepted Submission(s): 7364 Problem Description Today is Ignatius' birthday. He invites a…

确定比赛名次 Problem Description 有N个比赛队(1<=N<=500),编号依次为1,2,3,....,N进行比赛,比赛结束后,裁判委员会要将所有参赛队伍从前往后依次排名,但现在裁判委员会不能直接获得每个队的比赛成绩,只知道每场比赛的结果,即P1赢P2,用P1,P2表示,排名时P1在P2之前.现在请你编程序确定排名. Input 输入有若干组,每组中的第一行为二个数N(1<=N<=500),M:其中N表示队伍的个数,M表示接着有M行的输入数据.接下来的M行数据中,…

板子题不多说,上代码 #include<iostream> #include<cstdio> #include<cstring> using namespace std; ]; int find(int x){ ) return x; return F[x]=find(F[x]); } void bing(int a,int b){ int t1=find(a); int t2=find(b); if(t1!=t2) F[t1]=t2; } int main(){ in…

代码: #include<cstdio> #include<cstring> using namespace std; int n,m; int father[1005]; int Find(int a) { int r=a; while(father[a]!=a) { a=father[a]; } father[r]=a; return a; } void Union(int a,int b) { a=Find(a); b=Find(b); if(a!=b) father[b]=…

题意:题意:一个人请人吃饭,相互认识的朋友在一张桌子,相互认识的朋友的意思是如果A认识B,B认识C,那么A.B.C是朋友,对于每组输入输出桌子的张数. Sample Input 2 5 3 1 2 2 3 4 5 5 1 2 5   Sample Output 2 4 代码: #include<iostream> #include<cstdio> using namespace std; ]; int Find(int k){ if(a[k]!=k) a[k]=Find(a[k])…

转自:http://blog.csdn.net/shahdza/article/details/7779230 [HDU]1213 How Many Tables 基础并查集★1272 小希的迷宫 基础并查集★1325&&poj1308 Is It A Tree? 基础并查集★1856 More is better 基础并查集★1102 Constructing Roads 基础最小生成树★1232 畅通工程 基础并查集★2120 Ice_cream's world I 基础并查集★212…

How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17946    Accepted Submission(s): 8822 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinn…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 简单的并查集 代码: #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #define maxn 1100 using namespace std; int parent[maxn]; int m,n; int Find(int x) { int s; ;s=pa…