今天项目要求随机从数据库中随机取出若干条数据,放到首页.那么要如何随机取出这个子集合呢?本人向到的方法如下: 1.假设数据量很少,如我数据库中只有10条数据,而我要求随机取出8条.对于这种低数据量,大可以一次过全部取出放到父集合当中,然后随机remove去两条. List<Model> list = new MyService().QueryList().ToList(); Random random=new Random(); //注意,不能在while里面创建random因子,因为这样会导…

Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], [1…

Given a set of distinct integers, S, return all possible subsets. Note: Elements in a subset must be in non-descending order. The solution set must not contain duplicate subsets. For example,If S = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], [1…

1.输入班级人数,统计每个人的姓名,性别,年龄:集合与数组 //Console.Write("请输入班级人数:"); //int a = int.Parse(Console.ReadLine()); //ArrayList al = new ArrayList(); //for (int i = 0; i < a;i++ ) //{ // string [] name =new string[3]; // Console.Write("请输入第{0}个人的姓名:&quo…

首先说明这是一个数学的排列组合问题C(m,n) = m!/(n!*(m-n)!) 比如:有集合('粉色','红色','蓝色','黑色'),('38码','39码','40码'),('大号','中号') 分别从每一个集合中取出一个元素进行组合,问有多少种组合?解:C(4,1) * C(3,1) * C(2,1) = (4!/(1!*(4-1)!)) * (3!/(1!*(3-1)!)) * (2!/(1!*(2-1)!)) = 24/6 * 6/2 * 2 = 4 * 3 * 2 = 24(种)…

Given a set of distinct integers, nums, return all possible subsets. Note: The solution set must not contain duplicate subsets. For example,If nums = [1,2,3], a solution is: [ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ] 题目标签:Array 方法 1: 题目给了我们一…

工作中经常用到的linq根据传入数据集合查询对应子级数据,整理共享,希望大家都能用得上,代码中doublesArray 为父节点对应ID数据集合,再根据ID数据集合查询全部子级数据. //获取缓存数据 object obj = Caching.GetCache(CacheKey + UModel.RoleId); if (obj != null)//判读缓存数据是否null { SysFunList = (DataSet)obj; } else { string strSql = "select…

工作中经经常使用到的linq依据传入数据集合查询相应子级数据,整理共享,希望大家都能用得上,代码中doublesArray 为父节点相应ID数据集合,再依据ID数据集合查询所有子级数据. //获取缓存数据 object obj = Caching.GetCache(CacheKey + UModel.RoleId); if (obj != null)//判读缓存数据是否null { SysFunList = (DataSet)obj; } else { string strSql = "sele…

上代码 List<User> list = new ArrayList<User>(); User user1 = new User("第一位","用户1"); list.add(user1); User user2 = new User("第二位","用户2"); list.add(user2); User user3 = new User("第三位","用户3"…

We are given two arrays A and B of words.  Each word is a string of lowercase letters. Now, say that word b is a subset of word a if every letter in b occurs in a, including multiplicity.  For example, "wrr" is a subset of "warrior", b…