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关于LowBee苦思冥想的结果(仅供参考):…
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我表示我很难过 Nitrous We will be discontinuing the Nitrous Development Platform and Cloud IDE on November 14th, 2016. 之前用的蛮顺手的,还支持多人联合开发,竟然不能再用了......…
圆形奖章给定半径的半径和圆形区域.另一个硬币的半径,然后在桌面上平稳.给定硬币的速(的大小和方向,vx,vy)和坐标(奖牌同心圆形区域,圆和心脏为源),Q币在一个圆形区域和多少下滑(不管是什么圆形区域的一部分被认为是),币碰到圆奖牌会反弹.能量不变(速度不变) 第一次做平面几何题 看了题解,题解的板子真好用 大概来说有三种情况.例如以下图 第一种是进入圆区而不碰撞,查看h和Rm+r的关系 另外一种是进入圆区且碰撞,查看h和Rm+r的关系 第三种是不进入圆区.查看方向向量和圆心到初始点向量这两个向…
  The 14th tip of DB Query Analyzer Ma Genfeng (Guangdong Unitoll Services incorporated, Guangzhou 510300) Abstract   In this essay I will demonstrate how to display the content of a certain function in DB2 by DB Query Analyzer.               Key wor…
A smooth sea never made a skillful mariner. 平静的海洋练不出熟练的水手. A smooth sea never made a skillful mariner, but a violent sea may kill a greenhand. When we are engaged in a relatively new vacation, the best way may be to follow the principle from easy to…
Problem Description In Geometry, the problem of track is very interesting. Because in some cases, the track of point may be beautiful curve. For example, in polar Coordinate system,ρ=cos3θ is like rose, ρ=1−sinθ is a Cardioid, and so on. Today, there…
题意:给定四点的坐标(x,y),分别确定两直线,求出其交点,若重合or平行则输出相应信息 用四个点的坐标算出直线通式(ax+by+c=0)中的a,b,c,然后利用a,b,c计算出交点坐标(其他公式不够通用= =,比如斜率限制) 我利用两次平行判定重合 公式利用 初高中数学知识或代数知识 在草纸上仔细推导出来= =,让a,b,c为整数,比如可以演算得到a = y2-y1,b = x1-x2这一类公式. 详细Code如下: //给定四点,分别确定两直线,求出其交点,若重合or平行则输出相应信息 //…
Who am I? Coming October 18, 2016! 我是谁?2016.10.18 拭目以待! Don't worry. You will be a wow. Don't worry. I will be a wow and I will walk on my new road towards a splendid expert in industrial control. How many roads must a man walk down, before you call…
To live is to function, that is all there is in living. 活着就要发挥作用,这就是生活的全部内容. I often joke that my dream is to work any more but there is stll enough money to support an affluent life. Just a joke. And that may be because I am often feeling tired of m…