2018 ACM 国际大学生程序设计竞赛上海大都会赛重现赛 H - A Simple Problem with Integers (线段树,循环节) 链接:https://ac.nowcoder.com/acm/contest/163/H 来源:牛客网 链接:https://ac.nowcoder.com/acm/contest/163/H来源:牛客网 时间限制:C/C++ 2秒,其他语言4秒 空间限制:C/C++ 262144K,其他语言524288K 64bit IO Format: %ll…

A Simple Problem with Integers [题目链接]A Simple Problem with Integers [题目类型]线段树 成段增减+区间求和 &题解: 线段树 成段增减+区间求和 模板题 这种题真的应该理解并且可以流畅的独立码出来了 [时间复杂度]\(O(nlogn)\) &代码: #include <iostream> #include <cstdio> #include <cstring> using namespa…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 92127   Accepted: 28671 Case Time Limit: 2000MS 描述 You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operatio…

A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 53169 Accepted: 15897 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of ope…

A Simple Problem with Integers Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of…

题目:http://poj.org/problem?id=3468   A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 85851   Accepted: 26685 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with…

A Simple Problem with Integers   Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum o…

A Simple Problem with Integers Time Limit:5000MS   Memory Limit:131072K Case Time Limit:2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 83822   Accepted: 25942 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 105742   Accepted: 33031 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type o…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 112228   Accepted: 34905 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type o…

A Simple Problem with Integers Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://poj.org/problem?id=3468 Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given nu…

A Simple Problem with Integers Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://poj.org/problem?id=3468 Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given nu…

解题报告 题意: 略 思路: 线段树成段更新,区间求和. #include <iostream> #include <cstring> #include <cstdio> #define LL long long #define int_now int l,int r,int root using namespace std; LL sum[500000],lazy[500000]; void push_up(int root,int l,int r) { sum[ro…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 75541   Accepted: 23286 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 59046   Accepted: 17974 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

3212: Pku3468 A Simple Problem with Integers Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 2046  Solved: 892[Submit][Status][Discuss] Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of opera…

A Simple Problem with Integers   Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum o…

Pku3468 A Simple Problem with Integers Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 2173  Solved: 951[Submit][Status][Discuss] Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation i…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 110077   Accepted: 34272 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type o…

id=3468">点击打开链接题目链接 A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 63565   Accepted: 19546 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of…

F - A Simple Problem with Integers Time Limit:5000MS     Memory Limit:131072KB     64bit IO Format:%lld & %llu Description 给出了一个序列,你需要处理如下两种询问. "C a b c"表示给[a, b]区间中的值全部增加c (-10000 ≤ c ≤ 10000). "Q a b" 询问[a, b]区间中所有值的和. Input 第一行包…

地址 http://poj.org/problem?id=3468 线段树模板 要背下此模板 线段树 #include <iostream> #include <vector> #include <math.h> #include <algorithm> using namespace std; /* Sample Input 10 5 1 2 3 4 5 6 7 8 9 10 Q 4 4 Q 1 10 Q 2 4 C 3 6 3 Q 2 4 Sample…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 67511   Accepted: 20818 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

题目地址http://poj.org/problem?id=3468 题目大意很简单,有两个操作,一个 Q a, b 查询区间[a, b]的和 C a, b, c让区间[a, b] 的每一个数+c 第一次线段树的延时标记,花了好大的功夫才写好==! 很容易看出来使用使用线段树记录区间的和,但是难点在于每次修改的是一个区间而不是一个点 所以采用的方法就是每次做修改操作时,只将区间［a,b］的标记+c,而不是真正意义上的将区间[a, b] 的每一个值+c. 而当我们做查询操作时,就只需要将区间[a,…

转载请注明出处:http://blog.csdn.net/u012860063 Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for th…

Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. 题意…

题目: Problem Description Let A1, A2, ... , AN be N elements. You need to deal with two kinds of operations. One type of operation is to add a given number to a few numbers in a given interval. The other is to query the value of some element.   Input T…

Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 115624   Accepted: 35897 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some give…

http://poj.org/problem?id=3468 题目大意: 给你N个数还有Q组操作(1 ≤ N,Q ≤ 100000) 操作分为两种,Q A B 表示输出[A,B]的和   C A B X表示把[A,B]的所有数加上X 思路: 线段树的区间修改..... 昨天晚上改了老半天. 然后关机准备睡觉毕竟今天有实验..去洗个头..突然有灵感..急急忙忙的开电脑改了就对了~哈哈哈 PS:POJ AC 100了~ 因为混迹各个OJ,SO才100 用位运算优化*2  1600+MS,不用2200…