The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle.…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

原题链接在这里:https://leetcode.com/problems/house-robber-iii/ 题目: The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent hous…

原题链接在这里:https://leetcode.com/problems/house-robber/ 题目: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent…

本题和House Robber差不多,分成两种情况来解决.第一家是不是偷了,如果偷了,那么最后一家肯定不能偷. class Solution(object): def rob(self, nums): """ :type nums: List[int] :rtype: int """ if not nums: return 0 n = len(nums) if n == 1: return nums[0] if n == 2: return ma…

213. House Robber II     Total Accepted: 24216 Total Submissions: 80632 Difficulty: Medium Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will…

Description: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and…

题意:有一个整数序列,从中挑出一些数字,使得总和是最大,前提是,相邻的两个数字中只能挑其一.比如1 2 3 就只能挑2或者1和3. 思路:很直观的题,dp思想.降低规模,从小规模开始考虑.如果只有两个数字,那么结果很明显就能知道是其中之大者.假如已经知道了第 i 个之前的决策,那么第i+2个之前的决策也就知道了.前两个数字已经由人工得知,设为dp[0]和dp[1],那么dp[2]=max(dp[0]+nums[2], dp[1]).状态转移方程dp[i]=max(dp[i-1], dp[i-2]…

Here is my collection of solutions to leetcode problems. Related code can be found in this repo: https://github.com/zhuli19901106/leetcode LeetCode - Course Schedule LeetCode - Reverse Linked List LeetCode - Isomorphic Strings LeetCode - Count Primes…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

337. House Robber III Total Accepted: 18475 Total Submissions: 47725 Difficulty: Medium The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has…

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All houses at this place are arranged in a circle. That means the first house is the neighbor of the last one. Meanwhile, adjacent…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle. …

The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the "root." Besides the root, each house has one and only one parent house. After a tour, the smart thief realized that "all hou…

198. 打家劫舍 198. House Robber 题目描述 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 每日一算法2019/5/8Day 5LeetCode198. House Robber 示例 1: 输入: [1,2,3,1] 输出: 4 解释:…

Leetcode之动态规划(DP)专题-198. 打家劫舍(House Robber) 你是一个专业的小偷,计划偷窃沿街的房屋.每间房内都藏有一定的现金,影响你偷窃的唯一制约因素就是相邻的房屋装有相互连通的防盗系统,如果两间相邻的房屋在同一晚上被小偷闯入,系统会自动报警. 给定一个代表每个房屋存放金额的非负整数数组,计算你在不触动警报装置的情况下,能够偷窃到的最高金额. 示例 1: 输入: [1,2,3,1] 输出: 4 解释: 偷窃 1 号房屋 (金额 = 1) ,然后偷窃 3 号房屋 (金额…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 递归 + 记忆化 动态规划 优化动态规划空间 日期 [LeetCode] 题目地址:https://leetcode.com/problems/house-robber/ Total Accepted: 67398 Total Submissions: 196356 Difficulty: Easy 题目描述 You are a profess…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/house-robber-ii/description/ 题目描述: You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed. All h…

题目简述 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will…

https://leetcode.com/submissions/detail/56095603/ 这是一道不错的DP题!自己想了好久没有清晰的思路,参看大神博客!http://siukwan.sinaapp.com/?p=1013 我自己的感悟: 对于树的的前序遍历(根-左-右):编写代码时,有效代码(处理函数)写在递归左子树之后,递归右子树之前: 中序遍历(左-根-右)用于二叉排序树的顺序输出,编写代码时,有效代码(处理函数)写在递归左右子树之前: 后序遍历(左-右-根),有效代码写在递归左…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

Note: This is an extension of House Robber. After robbing those houses on that street, the thief has found himself a new place for his thievery so that he will not get too much attention. This time, all houses at this place are arranged in a circle.…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

可以复用house robber的代码,两趟dp作为两种情况考虑,选最大值 #include <stdio.h> #define MAX 1000 #define max(a,b) ( (a)>(b)?(a):(b) ) }; int rob1(int* a, int n) { int i; dp[]=; dp[]=a[]; ;i<n;i++){ dp[i+]=max(dp[i],a[i]+dp[i-]); } return dp[n]; } int rob(int* nums,…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…

You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent houses have security system connected and it will autom…