Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence ( a1, a2, ..., aN) be any sequence ( ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, seq…

Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 37454   Accepted: 16463 Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ...…

Description A numeric sequence of ai is ordered ifa1 <a2 < ... < aN. Let the subsequence of the given numeric sequence (a1,a2, ..., aN) be any sequence (ai1,ai2, ..., aiK), where 1 <=i1 < i2 < ... < iK <=N. For example, sequence (1…

本题大意:和LIS一样 本题思路:用dp[ i ]保存前 i 个数中的最长递增序列的长度,则可以得出状态转移方程dp[ i ] = max(dp[ j ] + 1)(j < i) 参考代码: #include <iostream> #include <cstring> #include <algorithm> using namespace std; ; int a[maxn], dp[maxn]; int main () { ; cin >> n;…

题目链接 最长上升子序列O(n*log(n))的做法,只能用于求长度不能求序列. #include <iostream> #include <algorithm> using namespace std; ; int s[N],x; int main() { int n; while(cin>>n){ ; ;i<n;i++){ cin>>x; ||s[top-]<x) s[top++]=x; else s[upper_bound(s,s+top,…

Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence ( a1, a2, ..., aN) be any sequence ( ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK <= N. For example, seq…

Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 66763   Accepted: 29906 Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ...…

题目链接:http://poj.org/problem?id=2533 Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 55459   Accepted: 24864 Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the…

Longest Ordered Subsequence Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 47465   Accepted: 21120 Description A numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ...…

Longest Ordered Subsequence DescriptionA numeric sequence of ai is ordered if a1 < a2 < ... < aN. Let the subsequence of the given numeric sequence (a1, a2, ..., aN) be any sequence (ai1, ai2, ..., aiK), where 1 <= i1 < i2 < ... < iK…