HDU 3909 DLX】的更多相关文章

http://blog.csdn.net/sr_19930829/article/details/39756513 http://www.kuangbin.net/archives/hdu4069-dlx http://acm.hdu.edu.cn/showproblem.php?pid=3909 还是不会DLX哎= = 这题先放着吧…
思路:裸的DLX解数独.关键是建图,感觉还不如写个dfs直接,DLX写这个的代码很烦. #include<set> #include<map> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<cstdlib> #include<cstring> #include&l…
思路:裸的DLX重复覆盖 #include<set> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<cstdlib> #include<cstring> #include<iostream> #include<algorithm> #define pb…
思路:二分枚举建边,用DLX判断是否满足. #include<set> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<cstdlib> #include<cstring> #include<iostream> #include<algorithm> #…
Lamp Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 771    Accepted Submission(s): 230 Special Judge Problem Description There are several switches and lamps in the room, however, the connecti…
Description As we know,the fzu AekdyCoin is famous of math,especially in the field of number theory.So,many people call him "the descendant of Chen Jingrun",which brings him a good reputation.  AekdyCoin also plays an important role in the ACM_D…
Description N cities of the Java Kingdom need to be covered by radars for being in a state of war. Since the kingdom has M radar stations but only K operators, we can at most operate K radars. All radars have the same circular coverage with a radius…
题目大意: 有一堆雷达工作站,安放至多k个人在这些工作站中,找到一个最小的雷达监控半径可以使k个工作人所在的雷达工作站覆盖所有城市 二分半径的答案,每次利用dlx的重复覆盖来判断这个答案是否正确 #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> #include <queue> #include <climits> #includ…
思路:做法与9*9的一样.只不过是变量. #include<set> #include<map> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<cstdlib> #include<cstring> #include<iostream> #include…
思路:把每个点拆成(d+1)*n列,行数为可拆分区间数.对所有的有i号点拆分出来的行都要建一条该行到i列的边,那么就能确保有i号点拆出来的行只能选择一行. #include<set> #include<cmath> #include<queue> #include<cstdio> #include<vector> #include<string> #include<cstdlib> #include<cstring&…