Dividing Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 14861    Accepted Submission(s): 4140 Problem Description Marsha and Bill own a collection of marbles. They want to split the collection…

Dividing Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 18190    Accepted Submission(s): 5080 Problem Description Marsha and Bill own a collection of marbles. They want to split the collection…

link:http://acm.hdu.edu.cn/showproblem.php?pid=1059 最简单的那种 #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> #include <cmath> #include <cctype> #include <algorithm> #include <queue>…

有价值为1~6的宝物各num[i]个,求能否分成价值相等的两部分. #include <iostream> #include <cstring> #include <string> #include <cstdio> #include <cmath> #include <algorithm> #include <vector> #include <queue> #include <map> #def…

Problem Description Marsha and Bill own a collection of marbles. They want to split the collection among themselves so that both receive an equal share of the marbles. This would be easy if all the marbles had the same value, because then they could…

1.Robberies 连接 :http://acm.hdu.edu.cn/showproblem.php?pid=2955     背包;第一次做的时候把概率当做背包(放大100000倍化为整数):在此范围内最多能抢多少钱  最脑残的是把总的概率以为是抢N家银行的概率之和… 把状态转移方程写成了f[j]=max{f[j],f[j-q[i].v]+q[i].money}(f[j]表示在概率j之下能抢的大洋);    正确的方程是:f[j]=max(f[j],f[j-q[i].money]*q[i…

HDU 动态规划(46道题目)倾情奉献~ [只提供思路与状态转移方程] Robberies http://acm.hdu.edu.cn/showproblem.php?pid=2955      背包;第一次做的时候把概率当做背包(放大100000倍化为整数):在此范围内最多能抢多少钱  最脑残的是把总的概率以为是抢N家银行的概率之和… 把状态转移方程写成了f[j]=max{f[j],f[j-q[i].v]+q[i].money}(f[j]表示在概率j之下能抢的大洋);          正确的…

一.背包问题 最基础的一类动规问题.相似之处在于给n个物品或无穷多物品或不同种类的物品,每种物品仅仅有一个或若干个,给一个背包装入这些物品,要求在不超出背包容量的范围内,使得获得的价值或占用体积尽可能大,这一类题的动规方程f[i]一般表示剩余容量为i时取得的最大价值或最大占用体积.或者有多维状态,分别表示不同种物品的剩余量 1.Wikioi 1014 装箱问题 题目描写叙述 Description 有一个箱子容量为V(正整数,0<＝V<＝20000).同一时候有n个物品(0<n<＝…

[BZOJ3872]Ant colony(二分,动态规划) 题面 又是权限题... Description There is an entrance to the ant hill in every chamber with only one corridor leading into (or out of) it. At each entry, there are g groups of m1,m2,...,mg ants respectively. These groups will ent…

1.Robberies 连接 :http://acm.hdu.edu.cn/showproblem.php?pid=2955      背包;第一次做的时候把概率当做背包(放大100000倍化为整数):在此范围内最多能抢多少钱  最脑残的是把总的概率以为是抢N家银行的概率之和- 把状态转移方程写成了f[j]=max{f[j],f[j-q[i].v]+q[i].money}(f[j]表示在概率j之下能抢的大洋);     正确的方程是:f[j]=max(f[j],f[j-q[i].money]*q…