poj3273 Monthly Expense(二分搜索)】的更多相关文章

Monthly Expense Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 25959   Accepted: 10021 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and…
/* Monthly Expense Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 10757 Accepted: 4390 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and re…
题目链接:http://poj.org/problem?id=3273   Monthly Expense Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 29231   Accepted: 11104 Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run th…
https://vjudge.net/problem/POJ-3273 认真审题,代码仔细!!ans的初值应该是1 #include<iostream> #include<cstdio> #include<queue> #include<cstring> #include<algorithm> #include<cmath> #include<map> #define lson l, m, rt<<1 #def…
传送门 https://www.cnblogs.com/violet-acmer/p/9793209.html 题意: 有 N 天,第 i 天会有 a[ i ] 的花费: 将这 N 天分成 M 份,每份包含 1 天或连续的多天: 每份的花费为包含的天数花费的加和,求最大花费的最小值. 题解: 二分搜索答案. AC代码: #include<iostream> #include<cstdio> using namespace std; ; int N,M; int totMoney;…
Description Farmer John ≤ moneyi ≤ ,) that he will need to spend each day over the next N ( ≤ N ≤ ,) days. FJ wants to create a budget ≤ M ≤ N) fiscal periods called or more consecutive days. Every day is contained in exactly one fajomonth. FJ's goal…
题目:http://poj.org/problem?id=3273 思路:通过定义一个函数bool can(int mid):=划分后最大段和小于等于mid(即划分后所有段和都小于等于mid) 这样我们转化为求 满足该函数的 最小mid.即最小化最大值,可以通过二分搜索来做,要注意二分的边界.WR了好几次. 代码: #include<iostream> #include<string> #include<cstdlib> #include<cstdio> u…
Description Farmer John is an astounding accounting wizard and has realized he might run out of money to run the farm. He has already calculated and recorded the exact amount of money (1 ≤ moneyi ≤ 10,000) that he will need to spend each day over the…
查看原题 边界,就是边界和思维,怎么有效的判断中间值是大了还是小了,以及准确的找到边界!一个<写成<=就前功尽弃,还特别难找到错误! #include <cstdio> #include <algorithm> ; int N, M; int A[maxN]; using namespace std; int main(void) { == scanf("%d%d", &N, &M)) { , l = , m, sum, cnt, i…
    Description Farmer John是一个令人惊讶的会计学天才,他已经明白了他可能会花光他的钱,这些钱本来是要维持农场每个月的正常运转的.他已经计算了他以后N(1<=N<=100,000)个工作日中每一天的花费moneyi(1<=moneyi<=10,000),他想要为他连续的M(1<=M<=N)个被叫做“清算月”的结帐时期做一个预算,每一个“清算月”包含一个工作日或更多连续的工作日,每一个工作日都仅被包含在一个“清算月”当中. FJ的目标是安排这些“…