在一个项目的截止日期之前,如果工期有空闲则可能可以开展其他项目,提高效益.本题考查动态规划.数组dp[i][t]表示在截止时间为t时,前i个项目工作安排能够产生的最大收益,而前i个项目的截止时间都不大于t. //#include "stdafx.h" #include <iostream> #include <algorithm> #include <memory.h> using namespace std; struct node { // pr…

PAT顶级 1002. Business (35) As the manager of your company, you have to carefully consider, for each project, the time taken to finish it, the deadline, and the profit you can gain, in order to decide if your group should take this project. For example…

背包问题,把任务按截止日期排序,再按背包问题处理~ #include<bits/stdc++.h> using namespace std; ; struct node { int c; int w; int ddl; }Node[maxn]; int dp[maxn]; bool cmp (node a,node b) { return a.ddl<b.ddl; } int main () { int N; ; scanf ("%d",&N); ;i<…

γ = 1/scale =1/0.902 α = exp(−(Intercept)γ)=exp(-(7.111)*γ) > library(survival) > myfit=survreg(Surv(futime, fustat)~1 , ovarian, dist="weibull",scale=0) > summary(myfit) Call: survreg(formula = Surv(futime, fustat) ~ 1, data = ovarian,…

1005 Programming Pattern (35 分) Programmers often have a preference among program constructs. For example, some may prefer if(0==a), while others may prefer if(!a). Analyzing such patterns can help to narrow down a programmer's identity, which is use…

后缀数组.排序之后得到height数组,然后从上到下将height>=len的都分为一组,然后找到第一组个数最多的输出即可. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> #include<vector> #incl…

Given a list of N integers A1, A2, A3,...AN, there's a famous problem to count the number of inversions in it. An inversion is defined as a pair of indices i < j such that Ai > Aj. Now we have a new challenging problem. You are supposed to count the…

As the manager of your company, you have to carefully consider, for each project, the time taken to finish it, the deadline, and the profit you can gain, in order to decide if your group should take this project. For example, given 3 projects as the…

博客出处:http://blog.csdn.net/zhoufenqin/article/details/50497791 题目出处:https://www.patest.cn/contests/pat-a-practise 1001 题意:给出a+b,计算c=a+b,将c输出时每三个数加一个“,” 思路:数据范围比较小,根据特殊的数据范围,也可特殊求解,不解释 #include<iostream> #include<cstdio> #include<cstring>…

1008. Airline Routes (35) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 8000 B 判题程序 Standard 作者 CHEN, Yue Given a map of airline routes, you are supposed to check if a round trip can be planned between any pair of cities. Input Specification: Each input file cont…