UVa 10106 Product】的更多相关文章

高精度乘法问题,WA了两次是因为没有考虑结果为0的情况.  Product  The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each line in pair contains one multiplyer. The Output For each input pair of…
虽然是错的代码,但是还是想贴出来,最开始WA发现是没有考虑到乘积为0的情况,后来把a*0,0*a,a*0---0(若干个0),0--0(若干个0)*a都考虑进去了:可是还是WA,实在不懂先留在这儿.  Product  The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each…
Product The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each line in pair contains one multiplyer. The Output For each input pair of lines the output line should c…
package com.njupt.acm; import java.math.BigInteger; import java.util.Scanner; public class UVA_10106 { public static void main(String[] args) { Scanner scanner = new Scanner (System.in); while(scanner.hasNext()){ BigInteger a = scanner.nextBigInteger…
  Product of digits  For a given non-negative integer number N , find the minimal natural Q such that the product of all digits of Q is equal N . Input The first line of input contains one positive integer number, which is the number of data sets. Ea…
 Product  The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each line in pair contains one multiplyer. The Output For each input pair of lines the output line should…
这道题很简单.先将N用2,3,5,7(即10以内的素数)分解因数(需要先特殊判断N不为1),然后将可以合并的因数合并(如2*2合并成4,)这样求得的结果位数会减少,大小肯定会小一些.具体实现见代码. 我的解题代码如下: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <string>…
尝试一下java 的大数类 import java.util.*; import java.io.*; import java.math.BigInteger; public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); while(in.hasNextBigInteger()) { BigInteger a = in.nextBigInteger(), b =…
题意: 给n个数字的序列,C v p 把v位上的数字置成p , S l r代表求区间[l,r]各数字相乘得数的符号,对于每个S输出所得符号(’+‘,’-‘,’0‘) 分析: 开两个数组表示区间负数的个数.0的个数.当数字被改时,更新数组.查询时区间含0符号是0,再根据负数的个数的奇偶判断. #include <map> #include <set> #include <list> #include <cmath> #include <queue>…
题目 Volume 0. Getting Started 开始10055 - Hashmat the Brave Warrior 10071 - Back to High School Physics 10300 - Ecological Premium 458 - The Decoder 494 - Kindergarten Counting Game 414 - Machined Surfaces 490 - Rotating Sentences 445 - Marvelous Mazes…