1047. Remove All Adjacent Duplicates In String(删除字符串中的所有相邻重复项) 链接:https://leetcode-cn.com/problems/remove-all-adjacent-duplicates-in-string/ 题目: 给出由小写字母组成的字符串 S,重复项删除操作会选择两个相邻且相同的字母,并删除它们. 在 S 上反复执行重复项删除操作,直到无法继续删除. 在完成所有重复项删除操作后返回最终的字符串.答案保证唯一. 示例:…

lc57 Insert Interval 仔细分析题目,发现我们只需要处理那些与插入interval重叠的interval即可,换句话说,那些end早于插入start以及start晚于插入end的interval都可以保留.我们只需要两个指针,i&j分别保存重叠interval中最早start和最晚end即可,然后将interval [i, j]插入即可 class Solution { public int[][] insert(int[][] intervals, int[] newInte…

problem 1047. Remove All Adjacent Duplicates In String 参考 1. Leetcode_easy_1047. Remove All Adjacent Duplicates In String; 完…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 栈 日期 题目地址:https://leetcode.com/problems/remove-all-adjacent-duplicates-in-string/ 题目描述 Given a string S of lowercase letters, a duplicate removal consists of choosing two adjac…

题目如下: Given a string S of lowercase letters, a duplicate removal consists of choosing two adjacent and equal letters, and removing them. We repeatedly make duplicate removals on S until we no longer can. Return the final string after all such duplica…

1047. 删除字符串中的所有相邻重复项 1047. Remove All Adjacent Duplicates In String 题目描述 LeetCode1047. Remove All Adjacent Duplicates In String简单 Java 实现 import java.util.Stack; class Solution { public String removeDuplicates(String S) { if (S == null || S.length()…

题目如下: Given a string s, a k duplicate removal consists of choosing k adjacent and equal letters from s and removing them causing the left and the right side of the deleted substring to concatenate together. We repeatedly make k duplicate removals on …

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 智商题 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/swap-adjacent-in-lr-string/description/ 题目描述 In a string composed of 'L', 'R', and 'X' characters, like "RXXLRXRXL", a…

public class RemoveAllAdjacentDuplicatesInString { /* 解法一:栈 */ public String removeDuplicates(String S) { Stack<Character> stack=new Stack<>(); for (char c:S.toCharArray()){ if (stack.isEmpty()||c!=stack.peek()) stack.push(c); else stack.pop()…

LeetCode 80 Remove Duplicates from Sorted Array II [Array/auto] <c++> 给出排序好的一维数组,如果一个元素重复出现的次数大于两次,删除多余的复制,返回删除后数组长度,要求不另开内存空间. C++ 献上自己丑陋无比的代码.相当于自己实现一个带计数器的unique函数 class Solution { public: int removeDuplicates(std::vector<int>& nums) {…