题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/677 5-15 PAT Judge   (25分) The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Spe…

1075 PAT Judge (25分)   The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For eac…

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line…

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line…

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line…

/* * 1.主要就用了个sort对结构体的三级排序 */ #include "iostream" #include "algorithm" using namespace std; ]; struct Node { int id; ] = {-,-,-,-,-,-}; /* 记录每一题的分数 初始化为-2代表没答题 */ ; /* 记录总分 */ ; /* 记录得满分的题目总数 */ bool flag = false; /* 判断该用户能否上ranklist 默…

题意: 输入三个正整数N,K,M(N<=10000,K<=5,M<=100000),接着输入一行K个正整数表示该题满分,接着输入M行数据,每行包括学生的ID(五位整数1~N),题号和该题得分(-1表示没通过编译).输出排名,学生ID,总分和每一题的得分,第一优先为总分降序,第二优先为题目AC数降序,第三优先为学生ID升序(提交但未通过编译得分为0,未提交得分为-,不输出没有提交或者提交全都未通过编译的学生信息). trick: 测试点4为有学生先交了得到分的程序后该题后来又交了未通过编译…

A1075 PAT Judge (25)(25 分) The ranklist of PAT is generated from the status list, which shows the scores of the submittions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For…

PAT甲级:1025 PAT Ranking (25分) 题干 Programming Ability Test (PAT) is organized by the College of Computer Science and Technology of Zhejiang University. Each test is supposed to run simultaneously in several places, and the ranklists will be merged imme…

1025 PAT Ranking (25分) 1. 题目 2. 思路 设置结构体, 先对每一个local排序,再整合后排序 3. 注意点 整体排序时注意如果分数相同的情况下还要按照编号排序 4. 代码 #include<cstdio> #include<cmath> #include<cstring> #include<algorithm> using namespace std; struct stu{ int location_number; char…