LeetCode: Next Greater Element I】的更多相关文章

LeetCode--Next Greater Element I Question You are given two arrays (without duplicates) nums1 and nums2 where nums1's elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2. The Next…
Given a positive 32-bit integer n, you need to find the smallest 32-bit integer which has exactly the same digits existing in the integer n and is greater in value than n. If no such positive 32-bit integer exists, you need to return -1. Example 1: I…
Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the ar…
You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2. The Next Greater Number of a number x in nums1 is t…
原题链接在这里:https://leetcode.com/problems/next-greater-element-iii/description/ 题目: Given a positive 32-bit integer n, you need to find the smallest 32-bit integer which has exactly the same digits existing in the integer nand is greater in value than n.…
stack和map用好就行 public class Solution { public int[] nextGreaterElement(int[] findNums, int[] nums) { Stack maxNumSeq = new Stack(); Map<Integer, Integer> greaterNum = new HashMap<Integer, Integer>(); for (int i = nums.length-1; i >= 0; i--)…
第一题:寻找子集合中每个元素在原集合中右边第一个比它大的数. 想到了用哈希表存这个数的位置,但是没有想到可以直接用哈希表存next great,用栈存还没找到的数,没遍历一个数就考察栈中的元素小,小的话,这个数就是栈中数的next great,栈中的数肯定是下大上小. public int[] nextGreaterElement(int[] nums1, int[] nums2) { /* 通过map建立当前元素和其next great的映射 在建立映射时,用栈记录还没有映射(就是还没有找到n…
You are given two arrays (without duplicates) nums1 and nums2 where nums1’s elements are subset of nums2. Find all the next greater numbers for nums1's elements in the corresponding places of nums2. The Next Greater Number of a number x in nums1 is t…
Given a circular array (the next element of the last element is the first element of the array), print the Next Greater Number for every element. The Next Greater Number of a number x is the first greater number to its traversing-order next in the ar…
Given a positive 32-bit integer n, you need to find the smallest 32-bit integer which has exactly the same digits existing in the integer nand is greater in value than n. If no such positive 32-bit integer exists, you need to return -1. Example 1: In…