Given a string containing only digits, restore it by returning all possible valid IP address combinations. For example:Given "25525511135", return ["255.255.11.135", "255.255.111.35"]. (Order does not matter) 思路:回溯法 解向量X={str…

Restore IP Addresses Given a string containing only digits, restore it by returning all possible valid IP address combinations. For example:Given "25525511135", return ["255.255.11.135", "255.255.111.35"]. (Order does not mat…

题目链接 leetcode 93. Restore IP Addresses 题意 给定一段序列,判断可能组成ip数的所有可能集合 思路 可以采用模拟或者DFS的想法,把总的ip数分成四段,每段判断是否满足题意 class Solution { public: vector<string> ans; vector<string> restoreIpAddresses(string s){ if(!s.size()) return ans; solve(0,0,s,"&qu…

Given a string containing only digits, restore it by returning all possible valid IP address combinations. For example:Given "25525511135", return ["255.255.11.135", "255.255.111.35"]. (Order does not matter) 题解:深度优先搜索.用resul…

Given a string containing only digits, restore it by returning all possible valid IP address combinations. Example: Input: "25525511135" Output: ["255.255.11.135", "255.255.111.35"] 解法:Backtracking Java: public class Solution…

Given a string containing only digits, restore it by returning all possible valid IP address combinations. For example:Given "25525511135", return ["255.255.11.135", "255.255.111.35"]. (Order does not matter) 将给定字符串变为合法的IP地址(…

Given a string containing only digits, restore it by returning all possible valid IP address combinations. For example: Given "25525511135", return ["255.255.11.135", "255.255.111.35"]. (Order does not matter) 解题思路: 使用循环即可解决,…

Given a singly linked list L: L0→L1→…→Ln-1→Ln,reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→… You must do this in-place without altering the nodes' values. For example,Given {1,2,3,4}, reorder it to {1,4,2,3}. 思路: 先把链表分成两节,后半部分翻转,然后前后交叉连接. 大神的代码比我的简洁,注意分两节时用快…

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Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words. For example, givens = "leetcode",dict = ["leet", "code"]. Return true because &…