Leetcode 137. 只出现一次的数字 II - 题解 137. Single Number II 在线提交: https://leetcode.com/problems/single-number-ii/ 题目描述 给定一个非空整数数组,除了某个元素只出现一次以外,其余每个元素均出现了三次.找出那个只出现了一次的元素. 说明: 你的算法应该具有线性时间复杂度. 你可以不使用额外空间来实现吗? 示例 1: 输入: [2,2,3,2] 输出: 3 示例 2: 输入: [0,1,0,1,0,1…

LeetCode 137. Single Number II(只出现一次的数字 II)…

原题地址https://leetcode.com/problems/single-number-ii/ 题目描述Given an array of integers, every element appears three times except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现三次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime co…

Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…

137. Single Number II Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 数组仅有一个数出现一次,其他的出…

翻译 给定一个整型数组,除了某个元素外其余的均出现了三次. 找出这个元素. 备注: 你的算法应该是线性时间复杂度. 你能够不用额外的空间来实现它吗? 原文 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you…

Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…

137. 只出现一次的数字 II 给定一个非空整数数组,除了某个元素只出现一次以外,其余每个元素均出现了三次.找出那个只出现了一次的元素. 说明: 你的算法应该具有线性时间复杂度. 你可以不使用额外空间来实现吗? 示例 1: 输入: [2,2,3,2] 输出: 3 示例 2: 输入: [0,1,0,1,0,1,99] 输出: 99 PS: 对每一位单独统计出现1的次数, 如果出现的次数不能整除3说明唯一存在的数在这一位上为1, 时间复杂度O(32N) class Solution { publi…

没思路.网上找到的. 1. 将每一个int看成32位数,统计每一位出现的次数对3取余,所以需要开辟一个32大小的数组来统计每一位出现的次数 2. 对第一种思路进行简化,模拟3进制: three two one 0 0 1 表示出现了1个1 0 1 0 表示出现了2个1 0 1 1 表示出现了3个1.此时我们需要将其转化成三进制的: 1 0 0 并将后2位归零. 故而 two = (one & A[i] ) | two 已有1个1,又来1个1,则该位取1:或者本来就有2个1 one = one ^…

Given an array of integers, every element appears twice except for one. Find that single one. 本题利用XOR的特性, X^0 = X, X^X = 0, 并且XOR满足交换律. class Solution(object): def singleNumber(self, nums): """ :type nums: List[int] :rtype: int ""…