1021. Deepest Root (25) 时间限制 1500 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root t…
PAT甲级1021. Deepest Root 题意: 连接和非循环的图可以被认为是一棵树.树的高度取决于所选的根.现在你应该找到导致最高树的根.这样的根称为最深根. 输入规格: 每个输入文件包含一个测试用例.对于每种情况, 第一行包含正整数N(<= 10000),它是节点的数量,因此节点从1到N编号.然后按N-1行,每个都通过给定两个相邻节点的数字来描述一个边. 输出规格: 对于每个测试用例,打印一行中最深的根.如果这样的根不是唯一的, 打印他们的数字增加的顺序.在给定的图形不是树的情况下,打…
1021 Deepest Root (25)(25 分) A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest…
1021 Deepest Root (25 分)   A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest r…
A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: E…
https://pintia.cn/problem-sets/994805342720868352/problems/994805482919673856 A graph which is connected and acyclic can be considered a tree. The hight of the tree depends on the selected root. Now you are supposed to find the root that results in a…
本文同步发布在CSDN:https://blog.csdn.net/weixin_44385565/article/details/90409731 1107 Social Clusters (30 分)   When register on a social network, you are always asked to specify your hobbies in order to find some potential friends with the same hobbies. A …
A graph which is connected and acyclic can be considered a tree. The height of the tree depends on the selected root. Now you are supposed to find the root that results in a highest tree. Such a root is called the deepest root. Input Specification: E…
题意:有n个人,每个人有k个爱好,如果两个人有某个爱好相同,他们就处于同一个集合.问总共有多少个集合,以及每个集合有多少人,并按从大到小输出. 很明显,采用并查集.vis[k]标记爱好k第一次出现的人的编号,如果为0则表示未出现. 当前第i个人若也存在爱好k,则只要将i与vis[k]两个人合并即可. 最后father[i]相同的即处在同一个集合中. #include <iostream> #include <cstdio> #include <algorithm> #i…
此文章同步发布在我的CSDN上https://blog.csdn.net/weixin_44385565/article/details/89930332 1114 Family Property (25 分) This time, you are supposed to help us collect the data for family-owned property. Given each person's family members, and the estate(房产)info un…