[题目链接] https://www.lydsy.com/JudgeOnline/problem.php?id=1718 [算法] 用Tarjan算法找出所有e-DCC(边-双联通分量),然后将这张图缩点,答案即为(缩点后的树的叶子节点的个数 + 1) / 2 [代码] #include<bits/stdc++.h> using namespace std; #define MAXN 5010 #define MAXM 10010 struct edge { int to,nxt; } e[M…

tarjan求边双连通分量, 然后就是一棵树了, 可以各种乱搞... ------------------------------------------------------------------------------- #include<cstdio> #include<cstring> #include<algorithm>   using namespace std;   const int maxn = 5009;   struct edge { int…

1718: [Usaco2006 Jan] Redundant Paths 分离的路径 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 964  Solved: 503[Submit][Status][Discuss] Description In order to get from one of the F (1 <= F <= 5,000) grazing fields (which are numbered 1..F) to another f…

1718: [Usaco2006 Jan] Redundant Paths 分离的路径 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 1132  Solved: 590[Submit][Status][Discuss] Description     为了从F(1≤F≤5000)个草场中的一个走到另一个,贝茜和她的同伴们有时不得不路过一些她们讨厌的可怕的树．奶牛们已经厌倦了被迫走某一条路,所以她们想建一些新路,使每一对草场之间都会至少有两条相互分离的…

Redundant Paths Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13717   Accepted: 5824 Description In order to get from one of the F (1 <= F <= 5,000) grazing fields (which are numbered 1..F) to another field, Bessie and the rest of the…

Redundant Paths Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13712   Accepted: 5821 Description In order to get from one of the F (1 <= F <= 5,000) grazing fields (which are numbered 1..F) to another field, Bessie and the rest of the…

POJ 3177 Redundant Paths Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 12598   Accepted: 5330 Description In order to get from one of the F (1 <= F <= 5,000) grazing fields (which are numbered 1..F) to another field, Bessie and the re…

在看了春晚小彩旗的E技能(旋转)后就一直在lol……额抽点时间撸一题吧…… Redundant Paths Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8159   Accepted: 3541 Description In order to get from one of the F (1 <= F <= 5,000) grazing fields (which are numbered 1..F) to anot…

Redundant Paths Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11047   Accepted: 4725 Description In order to get from one of the F (1 <= F <= 5,000) grazing fields (which are numbered 1..F) to another field, Bessie and the rest of the…

POJ 3177 Redundant Paths POJ 3352 Road Construction 题目链接 题意:两题一样的.一份代码能交.给定一个连通无向图,问加几条边能使得图变成一个双连通图 思路:先求双连通.缩点后.计算入度为1的个数,然后(个数 + 1) / 2 就是答案(这题因为是仅仅有一个连通块所以能够这么搞,假设有多个,就不能这样搞了) 代码: #include <cstdio> #include <cstring> #include <algorithm…