[CF1223G/1240E]Wooden Raft 题解】的更多相关文章

前言 上午一场模拟赛(发布前很久,因为这题题解太长了),发现T3特别珂怕,打开题解,发现一行字: 不要再问了,再问就是CF 1240E 当场去世.jpg. 在下文中,我们记 \(A\) 为 \(a\) 数组中的最大值,在代码中就是 "_max" . 题意简述 题目链接 给出一组 \(n\) 块木板以及它们的长度 \(a_i\),现在要切割出两块木板使之长度为 \(x\) ,切割 \(x\) 块木板使之长度为 \(y\). 求 \(x \times y\) 的最大值. 题解 基本思想 我…
本题一看就知道是最长不减序列了,一想就以为是使用dp攻克了. 只是那是个错误的思路. 我就动了半天没动出来.然后看了看别人是能够使用dp的,只是那个比較难证明其正确性,而其速度也不快.故此并非非常好的解决方法. 所以我就直接硬算.硬模拟选择出非减子序列,选完就出答案了. 思路: 1 依照长度排序 2 依照不减原则选择重量,选一个,消灭一个. 最后消灭完了,就处理完成,答案就自然出来了. 原来是一道披着dp的外套的模拟题啊!一道伪装成难题的简单题. 代码也能够写的非常简洁: #include <s…
Wooden Signs 题目链接: http://acm.hust.edu.cn/vjudge/contest/127406#problem/E Description http://7xjob4.com1.z0.glb.clouddn.com/0f10204481da21e62f8c145939e5828e Input The input file contains several test cases, each of them as described below. The first…
Wooden Sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11627    Accepted Submission(s): 4807 Problem Description There is a pile of n wooden sticks. The length and weight of each stick a…
Wooden Sticks There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepa…
http://acm.hdu.edu.cn/showproblem.php?pid=1051 Problem Description There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs s…
嘤嘤嘤,实习半年多的小蒟蒻的第一篇博客(题解) 英文的: There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the m…
引言 <分布式系统理论进阶 - Paxos>介绍了一致性协议Paxos,今天我们来学习另外两个常见的一致性协议——Raft和Zab.通过与Paxos对比,了解Raft和Zab的核心思想.加深对一致性协议的认识. Raft Paxos偏向于理论.对如何应用到工程实践提及较少.理解的难度加上现实的骨感,在生产环境中基于Paxos实现一个正确的分布式系统非常难[1]: There are significant gaps between the description of the Paxos al…
前面一篇文章讲了Paxos协议,这篇文章讲它的姊妹篇Raft协议,相对于Paxos协议,Raft协议更为简单,也更容易工程实现.有关Raft协议和工程实现可以参考这个链接https://raft.github.io/,里面包含了大量的论文,视屏已经动画演示,非常有助于理解协议.概念与术语leader:领导者,提供客户提供服务(生成写日志)的节点,任何时候raft系统中只能有一个leader.follower:跟随者,被动接受请求的节点,不会发送任何请求,只会响应来自leader或者candida…
我要举报本次校赛出题人的消极出题!!! 官方题解请戳:http://3.scnuacm2015.sinaapp.com/?p=89(其实就是一堆代码没有题解) A. 树链剖分数据结构板题 题目大意:我没看,看不懂. 基本思路:我不会. 参考代码:找Oyk老师和Czj老师去. B. The background of water problem 题目大意(大写加粗的水题):给定$N$个学生和他们$K$个科目的成绩$S_i$,再给出各科目$K_i$的权重顺序$Q_i$,求排名之后,拥有id为$X$的…