POJ:2377-Bad Cowtractors】的更多相关文章

传送门:http://poj.org/problem?id=2377 Bad Cowtractors Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 17373 Accepted: 7040 Description Bessie has been hired to build a cheap internet network among Farmer John's N (2 <= N <= 1,000) barns that…
题目连接 http://poj.org/problem?id=2377 Bad Cowtractors Description Bessie has been hired to build a cheap internet network among Farmer John's N (2 <= N <= 1,000) barns that are conveniently numbered 1..N. FJ has already done some surveying, and found…
poj:4091:The Closest M Points 题目 描写叙述 每到饭点,就又到了一日几度的小L纠结去哪吃饭的时候了.由于有太多太多好吃的地方能够去吃,而小L又比較懒不想走太远,所以小L会先找到距离他近期的M家餐馆然后再做筛选. 小L如今所在的位置和每家餐馆的位置用同一笛卡尔坐标系中的点表示,而点与点之间的距离为欧几里得距离,对于点p = (p1, p2,..., pn)和点q = (q1,q2,..., qn),两者的距离定义例如以下 现给出在K维空间中小L所处的位置的坐标以及n个…
http://poj.org/problem?id=2377 bessie要为FJ的N个农场联网,给出M条联通的线路,每条线路需要花费C,因为意识到FJ不想付钱,所以bsssie想把工作做的很糟糕,她想要花费越多越好,并且任意两个农场都需要连通,并且不能存在环.后面两个条件保证最后的连通图是一棵树. 输出最小花费,如果没办法连通所有节点输出-1. 最大生成树问题,按边的权值从大道小排序即可,kruskal算法可以处理重边的情况,但是在处理的时候,不能仅仅因为两个节点在同一个连通子图就判断图不合法…
Bad Cowtractors Bessie has been hired to build a cheap internet network among Farmer John's N (2 <= N <= 1,000) barns that are conveniently numbered 1..N. FJ has already done some surveying, and found M (1 <= M <= 20,000) possible connection r…
题意:给出一个图,求出其中的最大生成树= =如果无法产生树,输出-1. 思路:将边权降序再Kruskal,再检查一下是否只有一棵树即可,即根节点只有一个 #include <cstdio> #include <iostream> #include <algorithm> #include <cstring> using namespace std; int N, M; // 节点,边的数量 struct edge { int from, to, dist;…
Bad Cowtractors Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 131072/65536K (Java/Other) Total Submission(s) : 1   Accepted Submission(s) : 1 Problem Description Bessie has been hired to build a cheap internet network among Farmer John's N (…
链接:传送门 题意:给 n 个点 , m 个关系,求这些关系的最大生成树,如果无法形成树,则输出 -1 思路:输入时将边权转化为负值就可以将此问题转化为最小生成树的问题了 /************************************************************************* > File Name: poj2377.cpp > Author: WArobot > Blog: http://www.cnblogs.com/WArobot/ &g…
Description Bessie has been hired to build a cheap internet network among Farmer John's N (2 <= N <= 1,000) barns that are conveniently numbered 1..N. FJ has already done some surveying, and found M (1 <= M <= 20,000) possible connection route…
http://poj.org/problem?id=1182 Description 动物王国中有三类动物A,B,C,这三类动物的食物链构成了有趣的环形.A吃B, B吃C,C吃A. 现有N个动物,以1-N编号.每个动物都是A,B,C中的一种,但是我们并不知道它到底是哪一种. 有人用两种说法对这N个动物所构成的食物链关系进行描述: 第一种说法是"1 X Y",表示X和Y是同类. 第二种说法是"2 X Y",表示X吃Y. 此人对N个动物,用上述两种说法,一句接一句地说出…