Seinfeld Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1368    Accepted Submission(s): 674 Problem Description I'm out of stories. For years I've been writing stories, some rather silly, just…

1692: [Usaco2007 Dec]队列变换 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 1383  Solved: 582[Submit][Status][Discuss] Description FJ打算带他的N(1 <= N <= 30,000)头奶牛去参加一年一度的“全美农场主大奖赛”.在这场比赛中,每个参赛者都必须让他的奶牛排成一列,然后领她们从裁判席前依次走过. 今年,竞赛委员会在接受队伍报名时,采用了一种新的登记规则:他们把所…

Wooden Sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15564    Accepted Submission(s): 6405 Problem Description There is a pile of n wooden sticks. The length and weight of each stick a…

FatMouse' Trade Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 56784    Accepted Submission(s): 19009 Problem Description FatMouse prepared M pounds of cat food, ready to trade with the cats g…

1691: [Usaco2007 Dec]挑剔的美食家 Time Limit: 5 Sec  Memory Limit: 64 MBSubmit: 786  Solved: 391[Submit][Status][Discuss] Description 与很多奶牛一样,Farmer John那群养尊处优的奶牛们对食物越来越挑剔,随便拿堆草就能打发她们午饭的日子自然是一去不返了.现在,Farmer John不得不去牧草专供商那里购买大量美味多汁的牧草,来满足他那N(1 <= N <= 100,…

http://codeforces.com/contest/738/problem/D Galya is playing one-dimensional Sea Battle on a 1 × n grid. In this game a ships are placed on the grid. Each of the ships consists of bconsecutive cells. No cell can be part of two ships, however, the shi…

4245: [ONTAK2015]OR-XOR Time Limit: 10 Sec  Memory Limit: 256 MBSubmit: 486  Solved: 266[Submit][Status][Discuss] Description 给定一个长度为n的序列a[1],a[2],...,a[n],请将它划分为m段连续的区间,设第i段的费用c[i]为该段内所有数字的异或和,则总费用为c[1] or c[2] or ... or c[m].请求出总费用的最小值. Input 第一行包含…

1098 均分纸牌 2002年NOIP全国联赛提高组  时间限制: 1 s  空间限制: 128000 KB  题目等级 : 黄金 Gold 题解   题目描述 Description 有 N 堆纸牌,编号分别为 1,2,…, N.每堆上有若干张,但纸牌总数必为 N 的倍数.可以在任一堆上取若于张纸牌,然后移动. 移牌规则为:在编号为 1 堆上取的纸牌,只能移到编号为 2 的堆上:在编号为 N 的堆上取的纸牌,只能移到编号为 N-1 的堆上:其他堆上取的纸牌,可以移到相邻左边或右边的堆上. 现在…

SB贪心,一开始还想着用二分,看了眼黄学长的blog,发现自己SB了... 最小道路=已选取的奶牛/道路总数. #include <iostream> #include <cstdio> #include <algorithm> using namespace std; ]; int n,m,d,l,ans; int main() { scanf("%d%d%d%d",&n,&m,&d,&l); ;i<=n;i+…

HDU 1257 最少拦截系统 题意:中文题不解释. 思路:网上有说贪心有说DP,想法就是开一个数组存每个拦截系统当前最高能拦截的导弹高度.输入每个导弹高度的时候就开始处理,遍历每一个拦截系统,一旦最高拦截高度比它高,就把当前拦截系统的高度调整为它的高度,如果访问到末尾都没有能拦截的系统,那么拦截系统加一. P.S:听说这题杭电数据有点水 /** Sample Input 8 389 207 155 300 299 170 158 65 Sample Output 2 **/ #include…