kuangbin专题七 POJ3468 A Simple Problem with Integers （线段树或树状数组）

【kuangbin专题七 POJ3468 A Simple Problem with Integers （线段树或树状数组）】的更多相关文章

kuangbin专题七 POJ3468 A Simple Problem with Integers （线段树或树状数组）

You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. Input The firs…

poj3468 A Simple Problem with Integers (线段树区间最大值)

A Simple Problem with Integers Time Limit: 5000MS Memory Limit: 131072K Total Submissions: 92127 Accepted: 28671 Case Time Limit: 2000MS 描述 You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operatio…

POJ3468 A Simple Problem with Integers —— 线段树区间修改

题目链接:https://vjudge.net/problem/POJ-3468 You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of nu…

POJ3468 A Simple Problem with Integers(线段树延时标记)

题目地址http://poj.org/problem?id=3468 题目大意很简单,有两个操作,一个 Q a, b 查询区间[a, b]的和 C a, b, c让区间[a, b] 的每一个数+c 第一次线段树的延时标记,花了好大的功夫才写好==! 很容易看出来使用使用线段树记录区间的和,但是难点在于每次修改的是一个区间而不是一个点所以采用的方法就是每次做修改操作时,只将区间［a,b］的标记+c,而不是真正意义上的将区间[a, b] 的每一个值+c. 而当我们做查询操作时,就只需要将区间[a,…

poj3468 A Simple Problem with Integers(线段树模板功能：区间增减，区间求和)

转载请注明出处:http://blog.csdn.net/u012860063 Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for th…