题目链接 第一次写三分 三分的基本模板 int SanFen(int l,int r) //找凸点 { ) { //mid为中点,midmid为四等分点 ; ; if( f(mid) > f(midmid) ) r = midmid; else l = mid; } return f(l) > f(r) ? l : r; } 这道题里面任意两点的距离都可以看作是一个凹函数,对任意t对所有凹函数取最大值构成一个新的凹函数,求新函数的最小值 #include<bits/stdc++.h>…

链接 需要特判一下n=1的时候 精度调太低会超时 #include <iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<stdlib.h> #include<vector> #include<cmath> #include<queue> #include<set> using namespace std…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4717 题意:给出n个点的坐标和运动速度(包括方向).求一个时刻t使得该时刻时任意两点距离最大值最小. 思路:每两个点之间的距离随时间的变化是一个开口向上的抛物线.把所有的抛物线画出来.然后每个时刻取最大值.发现这个最大值是单峰函数. struct point { double x,y; void get() { RD(x,y); } point(){} point(double _x,double…

The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 710    Accepted Submission(s): 290 Problem Description There are N points in total. Every point moves in certain direction and…

The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 72    Accepted Submission(s): 18 Problem Description There are N points in total. Every point moves in certain direction and cer…

The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 612    Accepted Submission(s): 250 Problem Description There are N points in total. Every point moves in certain direction and…

The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2122    Accepted Submission(s): 884 Problem Description There are N points in total. Every point moves in certain direction and…

The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 878    Accepted Submission(s): 353 Problem Description There are N points in total. Every point moves in certain direction and c…

The Moving Points Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 964    Accepted Submission(s): 393 Problem Description There are N points in total. Every point moves in certain direction and c…

Codeforce 1311 F. Moving Points 解析(思維.離散化.BIT.前綴和) 今天我們來看看CF1311F 題目連結 題目 略,請直接看原題. 前言 最近寫1900的題目更容易不看題解了,不知道是不是較少人\(AC\)的同難度題目會比較簡單. @copyright petjelinux 版權所有 觀看更多正版原始文章請至petjelinux的blog 想法 首先注意到,如果\(x\)座標上的前後兩點\(x_i,x_j\),\(x_i<x_j\),如果\(v[x_i]>v…