Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Output:…

描述:Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题目要求O(n)时间复杂度,O(1)空间复杂度. 思路1:初步使用暴力搜索,遍历…

Write an algorithm to determine if a number is "happy". A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the…

Given two integers L and R, find the count of numbers in the range [L, R](inclusive) having a prime number of set bits in their binary representation. (Recall that the number of set bits an integer has is the number of 1s present when written in bina…

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array. Example 1: Input: [3,0,1] Output: 2 Example 2: Input: [9,6,4,2,3,5,7,0,1] Output: 8 Note:Your algorithm should run in linear runtime…

Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values. Example 1: Input: 5 Output: True Explanation: The binary representation of 5 is: 101 Example 2: Input: 7 Output: False Ex…

136. Single Number -- Easy 解答 相同的数,XOR 等于 0,所以,将所有的数字 XOR 就可以得到只出现一次的数 class Solution { public: int singleNumber(vector<int>& nums) { int s = 0; for(int i = 0; i < nums.size(); i++) { s = s ^ nums[i]; } return s; } }; 参考 LeetCode Problems' So…

leetcode 136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解题思路: 如果以线性复杂度和…

LeetCode 136. Single Number(只出现一次的数字)…

136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…

Question 136. Single Number Solution 思路:构造一个map,遍历数组记录每个数出现的次数,再遍历map,取出出现次数为1的num public int singleNumber(int[] nums) { Map<Integer, Integer> countMap = new HashMap<>(); for (int i=0; i<nums.length; i++) { Integer count = countMap.get(nums…

题目 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 分析 由上一题改动而来,LeetCode 136 Single Nu…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 异或 字典 日期 [LeetCode] 题目地址:https://leetcode.com/problems/single-number/ Total Accepted: 183838 Total Submissions: 348610 Difficulty: Easy 题目描述 Given a non-empty array of integers…

Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Output:…

翻译 给定一个整型数组,除了某个元素外其余元素均出现两次. 找出这个仅仅出现一次的元素. 备注: 你的算法应该是一个线性时间复杂度. 你能够不用额外空间来实现它吗? 原文 Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could yo…

Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解法一:用map记录每个元素的次数,返回次数为1的元素 cl…

［抄题］: Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? [暴力解法]: 时间分析:n 空间分析:新建n的数组来存储 ［奇葩输出条件］…

［抄题］: Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Ou…

今天做了三道LeetCode上的简单题目,每道题都是用c++和Python两种语言写的.由于c++版的代码网上比較多.所以就仅仅分享一下Python的代码吧,刚学完Python的基本的语法,做做LeetCode的题目还是不错的,对以后找工作面试也有帮助! 刚開始就从AC率最高的入手吧! 1.Given an array of integers, every element appears twice except for one. Find that single one. Note: Your…

Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题目标签:Hash Table 题目给了我们一个 nums array, array 里…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. C…

原题地址https://leetcode.com/problems/single-number/ 题目描述Given an array of integers, every element appears twice except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现两次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime complexity.…

题目要求 Given a non-empty array of integers, every element appears twice except for one. Find that single one. 题目分析及思路 给定一个非空整数数组,除了一个元素只出现一次外,其余元素均出现两次.可以先对数组排序,然后遍历数组,若数组只有一个元素或连续两个元素不相同时则得到返回值,否则则去除这两个元素. python代码 class Solution: def singleNumber(sel…

1.题目大意 Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 给定一个数组的整数,数组中的每个元素都出现了两次.例外地,有一个元素只出现…

Linked Url:https://leetcode.com/problems/single-number/ Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it withou…

-------------------------------------- 一个数异或它自己会得到0,0异或n会得到n,所以可以用异或来消除重复项. AC代码如下: public class Solution { public int singleNumber(int[] nums) { int res=0; for(Integer i:nums) res^=i; return res; } } 题目来源: https://leetcode.com/problems/single-number…

Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 求出数组中只出现了一次的数(其他的数都出现了2次) 异或求解. public class…

题目描述: Given an array of integers, every element appears twice except for one. Find that single one. 解题思路: 参考别人的想法,用异或的方法实在是太绝了.A ^ A = 0 and A ^ B ^ A = B,因为只有一个是单着的,那么其他成对的两数相异或的结果是0,最后与单着的数异或还是为这个数. 代码如下: public class Solution { public int singleNu…

题目: Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 提示: 此题的主要是利用异或运算(xor)的特性:不同的输出1,相同的输出0.…

Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路:将数组元素逐个异或. 举个栗子:2  3  4  2  3 所有数字依次异或运算…