js验证两次输入的密码是否一致】的更多相关文章

原文链接:http://blog.csdn.net/DDfanL/article/details/51460324…
<div class="form-group"> <label class="col-sm-2 control-label font">新密码</label> <div class="col-xs-10"> <input type="password" class="form-control bt" name="pwd" id=&qu…
文章目录 1.实现的效果 2.编写的js文件(这里写在了api文件下) 3.在vue页面中引入(script) 4.页面代码 1.实现的效果 20220606_154646 2.编写的js文件(这里写在了api文件下) //验证纯数字 let regNumber = /^[0-9]*$/; //验证身份证 let IDRe18 = /^([1-6][1-9]|50)\d{4}(18|19|20)\d{2}((0[1-9])|10|11|12)(([0-2][1-9])|10|20|30|31)\…
js中 <script>function check(){ with(document.all){if(input1.value!=input2.value){alert("false")input1.value = "";input2.value = "";}else document.forms[0].submit();}}</script> html代码: <FORM METHOD=POST ACTION=&q…
实现效果: 1> 当输入确认密码时验证: 2> 当输入密码时验证: 实现步骤: 1.页面代码: <input class="form-control" type="password" id="password" name="password" ng-model="user.password" match-check="confrimPassword|confrimPassword…
手机号 /^[+]{0,1}(\d){1,3}[ ]?([-]?((\d)|[ ]){1,12})+$/ 传真~  /^(\d{3,4}-)?\d{7,8}$/ 邮箱 ^[a-z0-9]+([._\\-]*[a-z0-9])*@([a-z0-9]+[-a-z0-9]*[a-z0-9]+.){1,63}[a-z0-9]+$ URL  /^([0-9]|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.([0-9]|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(…
JS判断只能是数字和小数点 1.文本框只能输入数字代码(小数点也不能输入)<input onkeyup="this.value=this.value.replace(/\D/g,'')" onafterpaste="this.value=this.value.replace(/\D/g,'')"> 2.只能输入数字,能输小数点.<input onkeyup="if(isNaN(value))execCommand('undo')"…
1.文本框只能输入数字代码(小数点也不能输入)<input onkeyup="this.value=this.value.replace(/\D/g,'')" onafterpaste="this.value=this.value.replace(/\D/g,'')"> ---------------------------------- $(document).ready(function () {            $("#txt_Ro…
onkeyup="if(isNaN(value))execCommand('undo')" onafterpaste="if(isNaN(value))execCommand('undo')"…
html <div class="row"> <div class="panel panel-info"> <div class="panel-heading"> <h3 class="panel-title">{{ query_set }}密码修改</h3> </div> <div class="panel-body">…