［抄题］: Compare two version numbers version1 and version2.If version1 > version2 return 1; if version1 < version2 return -1;otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . cha…

比较两个版本号 version1 和 version2.如果 version1 大于 version2 返回 1,如果 version1 小于 version2 返回 -1, 除此以外 返回 0.您可能认为版本字符串非空,并且只包含数字和 . 字符.这个 . 字符不代表小数点,而是用于分隔数字序列.例如,2.5 不是“两个半”或“差一半到三个版本”,它是第二个第一级修订版本的第五个二级修订版本.以下是版本号排序的示例:0.1 < 1.1 < 1.2 < 13.37 详见:https://…

[LeetCode]165. Compare Version Numbers 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.me/ 题目地址:https://leetcode.com/problems/compare-version-numbers/description/ 题目描述: Compare two version numbers version1 and vers…

Question 165. Compare Version Numbers Solution 题目大意: 比较版本号大小 思路: 根据逗号将版本号字符串转成数组,再比较每个数的大小 Java实现: public int compareVersion(String version1, String version2) { String[] v1Arr = version1.split("\\."); String[] v2Arr = version2.split("\\.&qu…

Compare Version Numbers Compare two version numbers version1 and version2. If *version1* > *version2* return 1; if *version1* < *version2* return -1;otherwise return 0. You may assume that the version strings are non-empty and contain only digits an…

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

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题目: Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . char…

Compare two version numbers version1 and version1.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…

Compare two version numbers version1 and version2.If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0. You may assume that the version strings are non-empty and contain only digits and the . character.The . characte…