UVa 714 抄书(贪心+二分)】的更多相关文章

https://vjudge.net/problem/UVA-714 题意:把一个包含m个正整数的序列划分成k个非空的连续子序列,使得每个正整数恰好属于一个序列.设第i个序列的各数之和为S(i),你的任务是让所有S(i)的最大值尽量小. 思路:“最大值尽量小”问题. 区间的范围肯定是所有数中最大的一个至所有数之和,我们可以使用二分法来确定这样的一个值x,x尽量小并且每个区间都不大它. 题目要求的是前面的区间尽量小,那我们就需要贪心一下,从右边的数开始分配区间.需要注意的是,如果当前剩下来的待分配…
题目链接: 题目 Copying Books Time limit: 3.000 seconds 问题描述 Before the invention of book-printing, it was very hard to make a copy of a book. All the contents had to be re-written by hand by so called scribers. The scriber had been given a book and after s…
求使最大值最小,可以想到二分答案. 然后再根据题目意思乱搞一下,按要求输出斜杠(这道题觉得就这一个地方难). Code /** * UVa * Problem#12627 * Accepted * Time:0ms */ #include<iostream> #include<cstdio> #include<cctype> #include<ctime> #include<cstring> #include<cstdlib> #in…
F - 贪心+ 二分 Time Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %llu   Description   A set of n<tex2html_verbatim_mark> 1-dimensional items have to be packed in identical bins. All bins have exactly the same length l<tex2html_ver…
Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1566    Accepted Submission(s): 822 Problem Description Adam and Eve play a card game using a regular deck of 52 cards. The rule…
Heap Partition Time Limit: 2 Seconds      Memory Limit: 65536 KB      Special Judge A sequence S = {s1, s2, ..., sn} is called heapable if there exists a binary tree T with n nodes such that every node is labelled with exactly one element from the se…
题目传送门 /* 贪心/二分查找:首先对ai%=p,然后sort,这样的话就有序能使用二分查找.贪心的思想是每次找到一个aj使得和为p-1(如果有的话) 当然有可能两个数和超过p,那么an的值最优,每次还要和an比较 注意:不能选取两个相同的数 反思:比赛时想到了%p和sort,lower_bound,但是还是没有想到这个贪心方法保证得出最大值,还是题目做的少啊:( */ #include <cstdio> #include <algorithm> #include <cst…
The link to problem:Problem - D - Codeforces   D. Range and Partition  time limit per test: 2 seconds memory limit per test: 256 megabytes input: standard input output: standard output Given an array a of n integers, find a range of values [x,y] (x≤y…
题意:把一个包含m个正整数的序列划分成k个(1<=k<=m<=500)非空的连续子序列,使得每个正整数恰好属于一个序列(所有的序列不重叠,且每个正整数都要有所属序列).设第i个序列的各数之和为S(i),你的任务是让所有的S(i)的最大值尽量小.如果有多解,S(1)应尽量小,如果仍有多解,S(2)应尽量小,依此类推. 分析: 1.二分最小值x. 2.判断当前x是否满足条件时,从右往左尽量划分,若cnt<k,则从0开始依次标为分界点,这样可满足S(1),S(2),……,尽量小. #pr…
  Copying Books  Before the invention of book-printing, it was very hard to make a copy of a book. All the contents had to be re-written by hand by so called scribers. The scriber had been given a book and after several months he finished its copy. O…