Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100). A subsequence of…

Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and sis a short string (<=100). A subsequence of a…

原题 判断子序列 /** * @param {string} s * @param {string} t * @return {boolean} */ var isSubsequence = function(s, t) { var sl = s.length; var tl = t.length; if (sl === 0) { return true; } if (tl < sl) { return false; } var sindex = 0; for (let i = 0; i <…

题目详情 给定字符串 s 和 t ,判断 s 是否为 t 的子序列. 你可以认为 s 和 t 中仅包含英文小写字母.字符串 t 可能会很长(长度 ~= 500,000),而 s 是个短字符串(长度 <=100). 字符串的一个子序列是原始字符串删除一些(也可以不删除)字符而不改变剩余字符相对位置形成的新字符串.(例如,"ace"是"abcde"的一个子序列,而"aec"不是). 示例 1: s = "abc", t =…

[LeetCode]392. Is Subsequence 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/is-subsequence/description/ 题目描述: Given a string s and a string t, check if s is subsequence of t. You may assume that there is only lower case English letters…

392. Is Subsequence 水题,先是判断长度,长度t比s小,返回false,然后从左到右扫描t,然后同时扫描s,如果相同,s的index就往后拉一个,如果s的index等于s长度,返回true,否则,返回false.…

[思路] 判断s是否为t的子串,所以length(s)<=length(t).于是两个指针,一次循环. 将s.t转换为数组p1.p2. i为过程中s的匹配长度. i=0空串,单独讨论返回true. 当i=p1.length-1时返回true,否则循环结束返回false. [代码] class Solution { public boolean isSubsequence(String s, String t) { char []p1=s.toCharArray(); char []p2=t.to…

Given an unsorted array return whether an increasing subsequence of length 3 exists or not in the array. Formally the function should: Return true if there exists i, j, k such that arr[i] < arr[j] < arr[k] given 0 ≤ i < j < k ≤ n-1 else return…

Given an unsorted array of integers, find the length of longest increasing subsequence. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than…

Given strings S and T, find the minimum (contiguous) substring W of S, so that T is a subsequence of W. If there is no such window in S that covers all characters in T, return the empty string "". If there are multiple such minimum-length window…