Question 219. Contains Duplicate II Solution 题目大意:数组中两个相同元素的坐标之差小于给定的k,返回true,否则返回false 思路:用一个map记录每个数的坐标,如果数相同,如果坐标差小于k则返回true否则覆盖,继续循环 Java实现: public boolean containsNearbyDuplicate(int[] nums, int k) { Map<Integer, Integer> map = new HashMap<&…

Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between iand j is at most k. 题目大意:给定一个数组,和一个整数k,找出是否有两个不同的下标使得nums[i] = nums[j] ,并且…

Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and jis at most k. Subscribe to see which companies asked this question bool co…

Contains Duplicate II Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. Have you met this question in a…

一.Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 分析:先把数组排个序,然后遍历排序后…

 217 - Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Solution 1: s…

 1. Contains Duplicate 题目链接 题目要求: Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 代码如下:…

Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. class Solution { pub…

Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 解题思路 用一个set保存数组中的值,假…

每天一算:Contains Duplicate II 描述 给出1个整形数组nums和1个整数k,是否存在索引i和j,使得nums[i] == nums[j] 且i和j之间的差不超过k Example 1: Input: nums = [1,2,3,1], k = 3 Output: true. Example 2: Input: nums = [1,0,1,1], k = 1 Output: true Example 3: Input: nums = [1,2,3,1,2,3], k = 2…

219. Contains Duplicate II Easy Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. Example 1: Input:…

217. Contains Duplicate Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 判断数组是是否含有重复元素.…

原文题目: 217. Contains Duplicate 219. Contains Duplicate II 读题: 217只要找出是否有重复值, 219找出重复值,且要判断两者索引之差是否小于k //217. Contains Duplicate 46ms class Solution { public: bool containsDuplicate(vector<int>& nums) { set <int> s; //vector <int>::ite…

目录 题目链接 注意点 解法 小结 题目链接 Path Sum II - LeetCode 注意点 不要访问空结点 解法 解法一:递归,DFS.每当DFS搜索到新节点时,都要保存该节点.而且每当找出一条路径之后,都将这个保存为一维vector的路径保存到最终结果二维vector中.并且,每当DFS搜索到子节点,发现不是路径和时,返回上一个结点时,需要把该节点从一维vector中移除. /** * Definition for a binary tree node. * struct TreeNo…

目录 题目链接 注意点 解法 小结 题目链接 Subsets II - LeetCode 注意点 有重复的数字 数组可能是无序的,要先排序 解法 解法一:递归,只需要在Subsets中递归写法的基础上多加一句if(find(ret.begin(),ret.end(),tmp) == ret.end()) ret.push_back(tmp);j即可,因为已经排序了,所以加进去的如果已经存在就说明是重复的. class Solution { public: typedef vector<int>…

目录 题目链接 注意点 解法 小结 题目链接 Permutations II - LeetCode 注意点 不确定有几种排列 解法 解法一:因为有重复的数字所以排列的个数不确定几个,一直生成新的排列直到和原始的数列相同为止 class Solution { public: vector<int> nextPermutation(vector<int> nums) { int n = nums.size(),i = n-2,j = n-1; while(i >= 0 &…

219. Contains Duplicate II[easy] Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. 错误解法: class Solut…

Given an array of integers and an integer k, return true if and only if there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. (Old Version) Given an array of integers and an i…

Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. Example 1: Input: nums = [1,2,3,1], k = 3 Output:…

题目: Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and jis at most k. 给定一个整形数组和一个整数型数k,找出在这个数组中是否存在两个相同的数,并且这两个数的下标的距离小于k. "&q…

Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. 题目标签:Array, Hash Table 题目给了我们一个nums array 和一个 k, 让…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j]and the differen…

这是悦乐书的第193次更新,第197篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第53题(顺位题号是219).给定整数数组和整数k,找出数组中是否存在两个不同的索引i和j,使得nums [i] = nums [j]并且i和j之间的绝对差值小于等于k.例如: 输入:nums = [1,2,3,1],k = 3 输出:true 输入:nums = [1,0,1,1],k = 1 输出:true 输入:nums = [1,2,3,1,2,3],k = 2 输出:fals…

描述 Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. 分析 我的想法是:遍历该数组,并判断当前元素之后有没有和该元素相等的元素,如果有,就通过dis…

问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3704 访问. 给定一个整数数组和一个整数 k,判断数组中是否存在两个不同的索引 i 和 j,使得 nums [i] = nums [j],并且 i 和 j 的差的绝对值最大为 k. 输入: nums = [1,2,3,1], k = 3 输出: true 输入: nums = [1,0,1,1], k = 1 输出: true 输入: nums = [1,2,3…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 使用set 使用字典 日期 题目地址:https://leetcode.com/problems/contains-duplicate-ii/description/ 题目描述 Given an array of integers and an integer k, find out whether there are two distinct in…

Problem: Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. Summary: 给出数组nums,整型数k,找到数组中是否存在nums[i]和nums[j]相等且…

Given an array of integers and an integer k, find out whether there there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. 解题思路: HashMap,JAVA实现如下: public boolean containsNearby…

找出是否存在nums[i]==nums[j],使得 j - i <=k 这是map的一个应用 class Solution { public: bool containsNearbyDuplicate(vector<int>& nums, int k) { map<int,int> mii; ;i<nums.size() ;++i) { if (mii.find(nums[i]) != mii.end()) { if(i - mii[nums[i]] <=…

#-*- coding: UTF-8 -*-#遍历所有元素,将元素值当做键.元素下标当做值#存放在一个字典中.遍历的时候,#如果发现重复元素,则比较其下标的差值是否小于k,#如果小于则可直接返回True,否则更新字典中该键的值为新的下标class Solution(object):    def containsNearbyDuplicate(self, nums, k):        """        :type nums: List[int]        :typ…