Now you get a number N, and a M-integers set, you should find out how many integers which are small than N, that they can divided exactly by any integers in the set. For example, N=12, and M-integer set is {2,3}, so there is another set {2,3,4,6,8,9,…

How many integers can you find Time Limit : 12000/5000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 95   Accepted Submission(s) : 30 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description   Now…

题目给一个数字集合,问有多少个小于n的正整数能被集合里至少一个元素整除. 当然是容斥原理来计数了,计算1个元素组合的有几个减去2个元素组合的LCM有几个加上3个元素组合的LCM有几个.注意是LCM. 而[1,n]中能被x整除的数字有$ \lfloor \frac nx \rfloor$个,因为设有$t$个,$x \times t \leqslant n$. 计算多个数LCM利用:$lcm(a,b)=a/gcd(a,b)\times b $,$lcm(a,b,c)=lcm(a,lcm(b,c))$…

//设置m,Q小于n可以设置如何几号m随机多项整除 //利用已知的容斥原理 //ans = 数是由数的数目整除 - 数为整除的两个数的数的最小公倍数 + 由三个数字... #include<cstdio> #include<cstring> #include<iostream> using namespace std ; const int maxn = 110 ; typedef __int64 ll ; int a[maxn] ; int len ; int n ,…

题目链接: http://acm.hdu.edu.cn/showproblem.php? pid=1796 题目大意: 给你一个整数N.和M个整数的集合{A1.A2.-.Am}.集合内元素为非负数(包括零),求小于N的 正整数(1~N-1)中,能被M个整数的集合中随意一个元素整除的正整数个数. 比如N = 12.M = {2,3},在1~N-1中,能被2整除的数为{2,4,6.8.10},能被3整除的数为 {3.6,9}.则所求集合为{2,3,4.6,8,9,10},共7个,则答案为7. 思路:…

题目链接Hdu4135 Co-prime Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1412    Accepted Submission(s): 531 Problem Description Given a number N, you are asked to count the number of integers betwe…

How many integers can you find Time Limit: 12000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6429    Accepted Submission(s): 1847 Problem Description   Now you get a number N, and a M-integers set, you shoul…

Calculate the sum of two integers a and b, but you are not allowed to use the operator + and -. Example: Given a = 1 and b = 2, return 3. Credits:Special thanks to @fujiaozhu for adding this problem and creating all test cases. 这道题是CareerCup上的一道原题,难道…

Divide two integers without using multiplication, division and mod operator. If it is overflow, return MAX_INT. 这道题让我们求两数相除,而且规定我们不能用乘法,除法和取余操作,那么我们还可以用另一神器位操作Bit Operation,思路是,如果被除数大于或等于除数,则进行如下循环,定义变量t等于除数,定义计数p,当t的两倍小于等于被除数时,进行如下循环,t扩大一倍,p扩大一倍,然后更…

How many integers can you find Time Limit:5000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1796 Description   Now you get a number N, and a M-integers set, you should find out how many integers which are sm…