要求 给定一个非空数组,返回前k个出现频率最高的元素 示例 [1,1,1,2,2,3], k=2 输出:[1,2] 思路 出队逻辑,普通队列是先进先出,优先队列是按最大/最小值出队 通过堆实现优先队列,C++中用 priority_queue<Type, Container, Functional> 扫描一遍统计频率,排序找前k个出现频率最高的元素(nlogn) 维护一个含有k个元素的优先队列,遍历到的元素比队列中的最小频率元素的频率高,则取出最小频率的元素,将新元素入队(nlogk) 实现…

版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - Leetcode 347. Top K Frequent Elements - 题解 在线提交: https://leetcode.com/problems/top-k-frequent-elements/ Description Given a non-empty array of integers…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: 347. Top K Frequent ElementsYou may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

Given a non-empty array of integers, return the k most frequent elements. Example 1: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] Example 2: Input: nums = [1], k = 1 Output: [1] Note: You may assume k is always valid, 1 ≤ k ≤ number of unique ele…

［抄题］: Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 解题方法 字典 优先级队列 日期 题目地址:https://leetcode.com/problems/top-k-frequent-elements/description/ 题目描述 Given a non-empty array of integers, return the k most frequent elements. For example,…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. 其实最简单的就是想到就是用一个小顶堆实现,如果堆中元素个数小于K,则插入元素,如果大于K,则和堆顶比较,如果大于堆顶,则弹出堆顶,插入新元素. 自己实现红黑树有点难,好在C++ STL容器中,map,set和priority_queue都…

Given a non-empty array of integers, return the k most frequent elements. For example,Given [1,1,1,2,2,3] and k = 2, return [1,2]. Note: You may assume k is always valid, 1 ≤ k ≤ number of unique elements. Your algorithm's time complexity must be bet…